正则表达式是空的空格
[英]regular expression for is empty space
问题描述
I'm suresomeone of you know how to do this easily, I am trying to validate my inputs that only allows numbers, characters and/or an empty space which mean nothing in a string "" , so I have /^[0-9a-zA-Z]+$/ only missing that empty space in there. 
我很遗憾你知道如何轻松地做到这一点，我试图验证我的输入，只允许数字，字符和/或空格，这在字符串""没有任何意义，所以我有/^[0-9a-zA-Z]+$/只缺少那里的空白区域。 Seems I can't find the express for it, so I tried to create a variabel var emptyStr = "" and put it in there but don't really know how to write the correct syntax. 似乎我找不到它的表达式，所以我尝试创建一个varbel var emptyStr = ""并将其放在那里，但实际上并不知道如何编写正确的语法。
2 个解决方案
解决方案1
2 已采纳 2013-07-18 14:21:16
Use * rather than + . 使用*而不是+ 。 * is 0 or more times. *是0或更多次。 + is 1 or more times. +是1次或更多次。
/^[0-9a-zA-Z]*$/
解决方案2
0 2013-07-18 14:46:38
/^[A-z0-9\s]*$/
\\s还将捕获空间
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