[英]Parsing JSON response in javascript
That's the essence of my problem: It is necessary to list all "file": 那就是我的问题的本质:有必要列出所有“文件”:
{
"results": [{
"fromuserid": "Anonymous",
"touserid": "sd68Kbmc02",
"file": "943easd709bfb2f6",
"subject": "test",
"message": "ddd",
"createdAt": "2013-07-18T20:16:08.023Z",
"updatedAt": "2013-07-18T20:16:08.023Z",
"objectId": "bRDvHb4X4M"
}, {
"fromuserid": "Anonymous",
"touserid": "sd68Kbmc02",
"file": "ef763asd134a8125",
"subject": "test",
"message": "ddd",
"createdAt": "2013-07-18T20:13:56.997Z",
"updatedAt": "2013-07-18T20:13:56.997Z",
"objectId": "GaLWnbSFtg"
}, {
"fromuserid": "Anonymous",
"touserid": "sd68Kbmc02",
"file": "5e7ae0sd5f1b48d0",
"subject": "etesrtes",
"message": "dfv fv f",
"createdAt": "2013-07-18T16:09:20.403Z",
"updatedAt": "2013-07-18T16:09:20.403Z",
"objectId": "X83Qd7ctwi"
}]
}
I use: 我用:
$.getJSON("http://domain.me/user/show_user/name/?callback=?", function(data) {
$('#tile').html("<a href='http://domain.me/?img=" + data['results'][0]['file'] + "' target='_blank'><img src='http://domain.me/" + data['results'][0]['file'] + ".jpg'/></a>");
});
I get one line. 我得到一行。 You want to display all lines data['results'][0]['file'] . 您要显示所有行data ['results'] [0] ['file'] 。
$.getJSON("http://domain.me/user/show_user/name/?callback=?",
function(data)
{
var results = [];
$.each(data['results'], function(i, result) {
results.push("<a href='http://domain.me/?img=" + result['file'] + "' target='_blank'><img src='http://domain.me/" + result['file'] + ".jpg'/></a>");
});
$('#tile').html(results.join(""));
}
);
You have to parse and loop through the elements of your parsed JSON data, something you can easily do with Array.map()
(it is supported in all browsers but IE<9): 您必须解析并循环遍历已解析的JSON数据的元素,您可以使用Array.map()
轻松地完成Array.map()
除IE <9外,所有浏览器均支持该功能):
$.getJSON("http://domain.me/user/show_user/name/?callback=?", function(data) {
var html = data.results.map(function(item, index, array) {
return array[index].file;
});
$('#tile').html(html.join(", "));
});
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