Yii框架：如何检查复选框是否被选中？

Question

I want always show additional fields when chceckbox is unchecked and always hide when is checked.

I have checkbox:

<?php echo $form->checkBox($model2, 'ignore', array('onChange'=>'javascript:toggleUser2()')); ?>

js script:

<script>
                    function toggleUser2() {
                        if($('.User2_ignore').is(':checked')) {
                            $('.user2').hide();
                        } else {
                            $('.user2').show();
                        }
                    }
                    toggleUser2();
                </script> 

This always return false:

 console.log($('.User2_ignore').is(':checked'));

I also tried attr('checked') and val(), but they are returnig 'undefined'. Is there any way to check checkbox is checked or no?

Answer 1

Try Using this Jquery Code as shown below

$(document).ready(function(){
    $("input[type=checkbox]").change(function(){
        if($(this).is(":checked")){
            alert("Checked");
             //$(this).siblings("input[type=checkbox]").removeAttr("checked");
           }else{
            alert("Unchecked")  
           }
        });

});