[英]mysql group by select with conditional value
In my messages table I have following rows for example, 例如,在我的消息表中,我有以下几行,
|----|---------|--------------|------|
| id | user_id | message |status|
|====|=========|==============|======|
| 1 | 2 | msgs 11 | r |
|----|---------|--------------|------|
| 2 | 3 | msgs 12 | r |
|----|---------|--------------|------|
| 3 | 2 | msgs 13 | r |
|----|---------|--------------|------|
| 4 | 3 | msgs 14 | u |
|----|---------|--------------|------|
Now, I need to know two things for each user_id
现在,我需要为每个user_id
知道两件事
u
or not. 是否具有u
状态。 For example, a query like below select user_id, status, count(*) as totalMsg from messages group by user_id
Would brought me following rows 例如,像下面这样的查询select user_id, status, count(*) as totalMsg from messages group by user_id
中select user_id, status, count(*) as totalMsg from messages group by user_id
将带给我以下行
| user_id | status| totalMsg |
|=========|=======|==========|
| 2 | r | 2 |
|---------|-------|----------|
| 3 | r | 2 |
^
|------> I need this value to be 'u' because user 3 has a message u
My current query doesnt really gurantee that it will look for a u
in the status column. 我当前的查询并不能真正保证它将在状态列中查找u
。 Is that possible to do? 那有可能吗? If so how? 如果可以,怎么办?
MAX()
will work on this since r
is the least value based on the lexicographical order. MAX()
将对此起作用,因为r
是基于字典顺序的最小值。
SELECT user_ID,
MAX(status) status,
COUNT(*) totalMsg
FROM messages
GROUP BY user_ID
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