php正则表达式以＃开头的字符串中找不到任何重复的字符＃

Question

I'm looking for a regex to find words in string starting with # and not have any more repeated #

Given:

Hi I'm #hany #هانى my Friend #john#john is ##here . good bye#all .

I want the final result as this:

Hi I'm <a>#hany</a> <a>#هانى</a> my Friend #john#john is ##here . good bye#all .

I'm using this:

echo preg_replace('/(?!\b)#(\\S+)/','<a>$0</a>',$string);

I want only words starting with # and not have any more hashes like twitter hash-tags.

Answer 1

Try this pattern:

echo preg_replace('/(?<=\s)(#[^#\s]+)(?=\s)/', '<a>$0</a>' ,$string);

Output:

Hi I'm <a>#hany</a> <a>#هانى</a> my Friend #john#john is ##here . good bye#all .

Answer 2

Try with this:

echo preg_replace('~(?<=\s|^)#[^\s#]++~um', '<a>$0</a>', $string);

Explanations:

~             # pattern delimiter (instead of /, but it's the same)
(?<=          # open a lookbehind (means "preceded by")
    \s | ^    # a white character (space, tab, newline...) or the begining of the line
)             # close the lookbehind
#             # literal #
[^\s#]++      # all that is not a # or a white character, one or more times (possessive)
~             # delimiter
um            # u for unicode string, m for multiline mode