如何在查找表达式中使用带有sed的文件名

Question

Trying to answer Using Bash/Perl to modify files based on each file's name I ended in a point in which I don't know how to use find and sed all together.

Let's say there is a certain structure of files in which we want to change a line, appending the name of the file.

If it was a normal for loop we would do:

for file in dir/*
do
   sed -i "s/text/text plus $file/g" $file
done

But let's say we want to use find to change files from all subdirectories. In this case, I would use...

find . -type f -exec sed -i "s/text/text plus {}/g" {} \;
                                              ^
                                   it does not like this part

but these {} within sed are not accepted and I get the error

sed: -e expression #1, char 20: unknown option to `s'

I found some similar questions ( 1 ) but could not generalize it enough to make it understandable for me in this case.

I am sure you guys will come with a great solution for this. Thanks!

Answer 1

I really think the issue is that your files name contains a / that is why sed believes it start the options strings.

Replace / by @ in you sed command would do the job.

I try that on Linux BASH and it work perfectly

find . -type f -exec sed -i -e "s@text@test plus {}@g" {} \;

Answer 2

find would return pathnames (relative or absolute) depending upon the path you specify.

This would conflict with the delimiter you've specified, ie / . Change the delimiter for sed and you should be good:

find . -type f -exec sed -i "s|text|text plus {}|g" {} \;

EDIT: For removing the leading ./ from the paths, you can try:

find . -type f -exec sh -c '$f={}; f=${f/.\//}; sed -i "s|text|text plus ${f}|g" {}' \;

I'm certain that better solutions might exist ...