[英]Javascript regex to remove anything but numbers from the start of a string
I have some strings like this: 我有一些像这样的字符串:
var st1 = 'AU$99.95';
// Should return 99.95
//应该返回99.95
var st2 = 'AU.99.95';
// Should return 99.95
//应该返回99.95
var st1 = 'Blahblah $99,000';
// Should return 99,000
//应该返回99,000
My current regex gets me most of the way there, I'm just using string.replace(/[^0-9.,]/g, "");
我当前的正则表达式使我获得了大部分帮助,我只是在使用string.replace(/[^0-9.,]/g, "");
. 。
This works for all scenarios except for #2, when there is an allowed character that is before a number. 当#2之前的数字允许有字符时,此方法适用于除#2以外的所有方案。 I want to ONLY allow .
我只允许.
and ,
when there is a number preceding it. 和,
如果前面有数字。 How can I achieve this? 我该如何实现?
(I know I can write a javascript function to do this, but I'd rather take care of it all in the one regex replace) (我知道我可以编写一个javascript函数来做到这一点,但我宁愿在一个regex替换中解决所有问题)
EDIT: 编辑:
Apologies, small oversight. 道歉,小疏忽。 I also need to remove any text after the number (I assumed before/after numbers wouldn't make a difference, but apparently they do!). 我还需要删除数字之后的所有文本(我假设数字之前/之后不会有什么不同,但显然它们可以!)。 So: 所以:
var st4 = 'blahblah $.99,000AUD
// should return 99,000
var st4 = 'blahblah $.99,000AUD
//应该返回99,000
也许
string.replace(/^[^0-9]*/, "");
你可以这样做
str.replace(/^[^\d]*/,"").replace(/[^\d]*$/,"");
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