[英]Find out how often a value is between 2 dates in mysql
Hi with the follow code I request what dates are all in my database without duplicates. 嗨,下面的代码要求我数据库中的所有日期都没有重复。 Then I save it to an array. 然后我将其保存到数组。 In the array I also need an other value. 在数组中,我还需要另一个值。
The value I need is how much users are in one day in the database without duplicates. 我需要的价值是一天之内数据库中有多少用户,且没有重复。 For Example the array must later lookslike 23.07.2013 - 10, 24.07.2013 - 50 (users). 例如,该数组以后必须看起来像23.07.2013-10,24.07.2013-50(用户)。 I search for several hours but I don't find a good mysql query. 我搜索了几个小时,但找不到很好的mysql查询。
$query = "SELECT id, user, timestamp FROM stat WHERE timestamp BETWEEN '$datum1' AND '$datum2' GROUP BY timestamp";
$result = mysql_query($query,$db);
while($row = mysql_fetch_assoc($result))
{
mysql_num_rows($result);
$dataset1[] = array(strtotime($row['timestamp']),$number_of_users_on_this_day);
}
Try: 尝试:
$query = "SELECT id, user, COUNT(*) as count FROM stat WHERE timestamp BETWEEN '$datum1' AND '$datum2' GROUP BY timestamp"; $ query =“ SELECT id,user,COUNT(*)作为从“ $ datum1”和“ $ datum2” GROUP BY时间戳之间的统计时间戳记开始的计数”;
This will return the number of entries in the value 'count' 这将返回值“ count”中的条目数
if you want distinct data, in place of * use 如果您需要不同的数据,请使用*代替
COUNT(DISTINCT id) COUNT(DISTINCT ID)
with whatever field you want to be unique in place of 'id' 使用任何您想唯一代替“ id”的字段
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