简体   繁体   English

Android:膨胀布局的自定义视图

[英]Android: custom view from inflated layout

I am creating my own layout based on RelativeLayout as a class in code 我正在基于RelativeLayout作为代码中的类创建自己的布局

I have basics of the layout defined in XML R.layout.menu_layout (style, drawable for background, margin, height) 我有在XML R.layout.menu_layout定义的布局的基础(样式,可绘制背景,边距,高度)

If I would not need a class then I would call inflater to do this: 如果我不需要上课,那么我会打电话给充气机做到这一点:

RelativeLayout menuLayout = (RelativeLayout)inflater.inflate(R.layout.menu_layout, root);

But I would like to be calling my own class instead 但是我想打电话给我自己的课

MenuLayout menuLayout = new MenuLayout(myparams);

Since I need to create a class I need to somehow inherit the R.layout.menu_layout in constructor, how can I do that? 由于我需要创建一个类,因此需要以某种方式继承构造函数中的R.layout.menu_layout ,该怎么办? I guess there is no this.setLayout(res); 我猜没有this.setLayout(res); or this.setResource(res); this.setResource(res); in View. 在视图中。 Maybe I can use the other two parameters in View constructor but I did not find any tutorial how to do that either. 也许我可以在View构造函数中使用其他两个参数,但是我都没有找到任何教程来做到这一点。

public class MenuLayout extends RelativeLayout {
    public MenuLayout(Context context, AttributeSet attrs, int defStyle) {
        super(context, attrs, defStyle);
        initView(context);
    }

    public MenuLayout(Context context, AttributeSet attrs) {
        super(context, attrs);
        initView(context);
    }

    public MenuLayout(Context context) {
        super(context);
        initView(context);
    }

    private void initView(Context context) {
        View view = LayoutInflater.from(context).inflate(R.layout.menu_layout, null);
        addView(view);
    }
}

now you can use 现在您可以使用

MenuLayout menuLayout = new MenuLayout(myparams);

you can change constructors for params i think 您可以更改参数的构造函数,我认为

声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.

 
粤ICP备18138465号  © 2020-2024 STACKOOM.COM