通过XSLT将XML节点中的HTML转义为XSL-FO
[英]Escaped HTML in XML node via XSLT into XSL-FO
问题描述
I have a document that has to be generated as PDF. 
我有一个必须以PDF格式生成的文档。 I use Xalan and Apache FOP for processing an XML with XSLT into XSL-FO. 我使用Xalan和Apache FOP将带有XSLT的XML处理到XSL-FO中。
In my XML tree there is a node like this: 在我的XML树中，有一个像这样的节点：
<root>
<formula>
<text>3+10*10^-6*l</text>
<html><html xmlns="http://www.w3.org/1999/xhtml">3 · + 10 · 10<sup>-6</sup> · <i>l</i></html></html>
</formula>
</root>
How can I not only get proper HTML (by using disable-output-escaping="yes" ) but also get a node-set ( exsl:node-set ?) that I can process later on? 如何不仅获得适当的HTML（通过使用disable-output-escaping="yes" ），而且还获得一个节点集（ exsl:node-set ？），可以稍后对其进行处理？ I mean, I want to get a XSL-FO representation of that HTML formula in order to integrate that into my PDF output. 我的意思是，我想获得该HTML公式的XSL-FO表示形式，以便将其集成到我的PDF输出中。
Something like 就像是
<xsl:template match="xhtml:b">
<fo:inline font-weight="bold"><xsl:apply-templates/></fo:inline>
</xsl:template>
There may be a solution using saxon:parse() . 使用saxon:parse()可能有解决方案。 However, I cannot switch to that from Xalan-J. 但是，我不能从Xalan-J切换到该选项。
Is there a solution in my scenario? 我的方案有解决方案吗？
1 个解决方案
解决方案1
1 2013-07-25 17:40:28
You can certainly write one stylesheet to process with Xalan that does 您当然可以编写一个样式表来处理Xalan
<xsl:template match="html">
<xsl:value-of select="." disable-output-escaping="yes"/>
</xsl:template>
which then creates a serialized result document with the XHTML markup. 然后使用XHTML标记创建序列化的结果文档。
A second stylesheet could then process the result document of the first stylesheet eg 然后，第二个样式表可以处理第一个样式表的结果文档，例如
<xsl:template match="xhtml:html" xmlns:xhtml="http://www.w3.org/1999/xhtml">
<xsl:apply-templates/>
</xsl:template>
But you can't do it within one stylesheet with a result tree fragment as doe (disable-output-escaping) is a serialization feature and if you work with result tree fragments converted to a node set with the help of exsl:node-set or similar within one stylesheet there is no serialization happening. 但是您不能在一个带有结果树片段的样式表中完成此操作，因为doe （disable-output-escaping）是序列化功能，并且如果您使用exsl:node-set结果树片段转换为节点集，或一个样式表中的类似内容，则不会发生序列化。
Looking closer, as your snippet seems to contain references to undeclared entities like · 仔细看看，您的代码段似乎包含对未声明实体的引用，例如· I think the sample does not parse as XML at all so you would need to fix that first to do any XSLT processing. 我认为该示例根本不会解析为XML，因此您需要先进行修复以进行XSLT处理。
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