播放框架scala模板与枚举的case语句

Question

I have this scala template and want to use a case statement to render different html based on a matching enum value.

My template looks like this:

@(tagStatus: String)

 try {
   TagStatus.withName(tagStatus) match {
         case TagStatus.deployed => {<span class="label label-success">@tagStatus</span>}
         case TagStatus.deployedPartially => {<span class="label label-important">@tagStatus</span>}
         case TagStatus.deployedWithProblems => {<span class="label label-important">@tagStatus</span>}
     }
 } catch {
    {<span class="label label-important">??</span>}
 }

The enum looks something like this:

object TagStatus extends Enumeration{
   val deployed = Value("deployed")
   val deployedWithProblems = Value("deployed_with_problems")
   val deployedPartially = Value("deployed_partially")     
}

When i run this i get:

Compilation error
')' expected but 'case' found.
In C:\...\statusTag.scala.html at line 8.
5        case TagStatus.deployed => {<span class="label label-success">@tagStatus</span>}
6        case TagStatus.deployedPartially => {<span class="label label-important">@tagStatus</span>}
7        case TagStatus.deployedWithProblems => {<span class="label label-important">@tagStatus</span>}
8    } 
9 } catch {
10    {<span class="label label-important">??</span>}
11 }

I have not idea what is meant by this error message.

What am i missing in order to get this simple code snippet to compile?

Thanks!

Answer 1

toString is not compatible with match so convert the String to the enum using withName

You can do it like this - I am not quite sure of the Play syntax:

TagsStatus.withName(tagStatus) match {
  case TagStatus.deployed => {<span class="label label-success">@tagStatus</span>}
  case TagStatus.deployedPartially => {<span class="label label-important">@tagStatus</span>}
  case TagStatus.deployedWithProblems => {<span class="label label-important">@tagStatus</span>}
  case _ => {<span class="label label-important">??</span>}
}

BTW there is a common related issue concerning Scala pattern matching with lower case variable names

Answer 2

You don't have to use try here, just the wild card in you match (see: http://www.playframework.com/documentation/2.1.x/ScalaTemplateUseCases ).

@(tagStatus: String)

@tagStatus match {
    case TagStatus.deployed.toString => {<span class="label label-success">@tagStatus</span>}
    case TagStatus.deployedPartially.toString => {<span class="label label-important">@tagStatus</span>}
    case TagStatus.deployedWithProblems.toString => {<span class="label label-important">@tagStatus</span>}
    case _ => {<span class="label label-important">??</span>}
}