使用多个定界符分割字符串

Question

I want to split a string using python. I have successfully done it for one variable, but finding it hard to do it for 2.

The String :

Paragraph 4-2 says. i am going home$ early- Yes.

I need the output to be

Paragraph 4-2 says
i am going home 
early
Yes

The sentence should split from . , $ and - (But when it's between 2 numbers (4-2) it shouldn't split)

How can i do this?

text.split('.')

UPDATE

The new output should be like :

Paragraph 4-2 says.
i am going home$ 
early-
Yes.

Answer 1

>>> import re
>>> s = 'Paragraph 4-2 says. i am going home$ early- Yes'
>>>
>>> re.split(r'(?<!\d)\s*[.$-]\s*(?!\d)', s)
['Paragraph 4-2 says', 'i am going home', 'early', 'Yes']

• \\s*[.$-]\\s* matches any of . , $ or - surrounded by 0 or more spaces ( \\s* ).
• (?<!\\d) is a negative-lookbehind to ensure that the match is not preceded by a digit.
• (?!\\d) is a negative-lookahead to ensure that the match is not followed by a digit.

You can read more about lookarounds here .

Answer 2

>>> re.split('(?<=\D)[.$-](?=\D|$)', s)
['Paragraph 4-2 says', ' i am going home', ' early', ' Yes']
>>> 

(?<\\D)[.$-](?=\\D) will get the .$-, not followed or proceded by intergers. And the lookahead and lookbehind won't consume any string. So the string will be splitted only the .$-, without the numbers surrounded by it.

Edit:

>>> re.findall('.*?(?<=\D)[.$-](?=[\D]|$)', s)
['Paragraph 4-2 says.', ' i am going home$', ' early-', ' Yes.']

Answer 3

You can do this:

>>> import re
>>> st='Paragraph 4-2 says. i am going home$ early- Yes.'
>>> [m.group(1) for m in re.finditer(r'(.*?[.$\-])(?:\s+|$)',st)]
['Paragraph 4-2 says.', 'i am going home$', 'early-', 'Yes.']

If you are not going to modify the match group at all (with strip or something) you can also just use findall with the same regex:

>>> re.findall(r'(.*?[.$\-])(?:\s+|$)',st)
['Paragraph 4-2 says.', 'i am going home$', 'early-', 'Yes.']

The regex is explained here , but in summary:

(.*?[.$\-])  is the capture group containing:
 .*?          Any character (except newline) 0 to infinite times [lazy] 
    [.$\-]   Character class matching .$- one time

(?:\s+|$)    Non-capturing Group containing:
   \s+        First alternate: Whitespace [\t \r\n\f] 1 to infinite times [greedy] 
      |        or
       $      Second alternate: end of string

Depending on your strings, you may need to change the regex to (.*?[.$\\-])(?:[ ]+|$) if you don't want to match \\r\\n\\f with the \\s