为什么我的Python正则表达式找到两个匹配项？

Question

I am using [0x]?\\d+ to attempt to locate strings of the nature

0x10101
0x12341
12321

But when I run the regular expression on 0x3 , I get [u'0', u'x3'] .

It seems (to my untrained eye) that it is matching the shortest sequences? Or is there something wrong with my use of []? ?

Answer 1

[...] , which is called a character class , matches a single character.

You probably want:

(?:0x)?\d+