在特定行中用sed匹配和替换数字

Question

Using the Ubuntu 12.04 and vim 2.22.0, inside the vim editor I shall use:

:9;13;17;21s/\d\+/1/

to match digits before ^M (and sometime just digits without any tails) and change them to 1. This pattern occurs only in the beginning of the line #9,13,17 and 21. ie:

vi _ccc_info_datasets:

...
=====
2
../../automotive_susan_data/2.pgm output_large.corners.pgm -c > ftmp_out
691^M  // ---------> change to 1^M
=====
...

As I have understood, the same can't go with sed as like :

find . type f  -name "_ccc_info_datasets" -exec sed -i '9;13;17;21s/\d\+/1/' {} \;

for changing several files in bash. I have tried :

find . type f  -name "_ccc_info_datasets" -exec sed -i '9;13;17;21s/[0-9]{1;\}/1/' {} \;

but it executes with no errors but no results. Any helps is appreciated ;)

Answer 1

You cannot use sed like that. You need to use multiple sed replacements with -e switch like this:

sed -i.bak -e '9s/[0-9][0-9]*\('$'\r''\)/1\1/' -e '13s/[0-9][0-9]*\('$'\r''\)/1\1/' \
    -e '17s/[0-9][0-9]*\('$'\r''\)/1\1/' -e '21s/[0-9][0-9]*\('$'\r''\)/1\1/' file

Update: Though awk doesn't support inline editing I believe using awk will be much cleaner for this task. Consider below awk command:

awk 'NR ~ /^9|13|17|21$/{sub(/[0-9]+\r$/, "1\r")}1' file > _temp && mv _temp file