[英]C++ - Convert array of floats to std::string
I have an array of floats with a fixed length. 我有一系列固定长度的浮子。 Now I want to convert that array to a binary string.
现在我想将该数组转换为二进制字符串。
I cannot use const char *
because my string will contain null-bytes. 我不能使用
const char *
因为我的字符串将包含空字节。 How would I use memcpy in that case? 在这种情况下我如何使用memcpy? I have already tried a
reinterpret_cast<string *>
, but that won't work because the string is also/only storing pointers to the begin and end of the data (correct me if I am wrong). 我已经尝试过
reinterpret_cast<string *>
,但这不起作用,因为字符串也是/只存储指向数据开头和结尾的指针(如果我错了,请纠正我)。
I'm already constructing an empty string: 我已经构建了一个空字符串:
string s;
s.resize(arr_size);
But how would I copy an array of floats to that string? 但是我如何将一个浮点数组复制到该字符串?
Basically, I want to dump the memory region of a fixed float array to a string. 基本上,我想将固定浮点数组的内存区域转储到字符串。
Don't be to hard with me, I'm still learning c++ 不要和我一起努力,我还在学习c ++
Like this: 像这样:
#include <algorithm>
#include <string>
float data[10]; // populate
std::string s(sizeof data);
char const * p = reinterpret_cast<char const *>(data);
std::copy(p, p + sizeof data, &s[0]);
Note that sizeof data
is the same as 10 * sizeof(float)
, ie the number of bytes in the array. 请注意,
sizeof data
与10 * sizeof(float)
,即数组中的字节数。
Update: As suggested by James, you can do even better and write it all in one go: 更新:正如詹姆斯所建议的那样,你可以做得更好并一次性写出来:
char const * p = reinterpret_cast<char const *>(data);
std::string s(p, p + sizeof data); // beginning + length constructor
Or even: 甚至:
#include <iterator>
std::string s(reinterpret_cast<char const *>(std::begin(data)), // begin + end
reinterpret_cast<char const *>(std::end(data))); // constructor
Getting all of the bytes of the array into a string is easy: 将数组的所有字节都转换为字符串很简单:
std::string
bitwiseDump( float const* begin, float const* end )
{
return std::string( reinterpret_cast<char const*>( begin ),
reinterpret_cast<char const*>( end ) );
}
But why? 但为什么? There's nothing you can do with the string except copy it back into an array of the same type.
除了将其复制回相同类型的数组之外,您无法对该字符串执行任何操作。 (And even for that use,
std::vector<char>
or std::vector<unsigned char>
would be more natural. And less obfuscating.) (甚至对于那种用法,
std::vector<char>
或std::vector<unsigned char>
会更自然。而且不那么混淆。)
Take a look at this... 看看这个...
#include <iostream>
#include <array>
#include <string>
int main()
{
std::string floatString;
std::array<float, 5> data = {1.1f, 2.2f, 3.3f, 4.4f, 5.5f};
for (auto& element : data)
floatString.append(std::to_string(element));
std::cout << floatString;
std::cin.get();
}
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