[英]Find and update in nested json object
I used this code to find the required portion from the json object from sJhonny's Question我使用此代码从sJhonny's Question的 json 对象中找到所需的部分
Data Sample数据样本
TestObj = {
"Categories": [{
"Products": [{
"id": "a01",
"name": "Pine",
"description": "Short description of pine."
},
{
"id": "a02",
"name": "Birch",
"description": "Short description of birch."
},
{
"id": "a03",
"name": "Poplar",
"description": "Short description of poplar."
}],
"id": "A",
"title": "Cheap",
"description": "Short description of category A."
},
{
"Product": [{
"id": "b01",
"name": "Maple",
"description": "Short description of maple."
},
{
"id": "b02",
"name": "Oak",
"description": "Short description of oak."
},
{
"id": "b03",
"name": "Bamboo",
"description": "Short description of bamboo."
}],
"id": "B",
"title": "Moderate",
"description": "Short description of category B."
}]
};
Function to find查找功能
function getObjects(obj, key, val) {
var objects = [];
for (var i in obj) {
if (!obj.hasOwnProperty(i)) continue;
if (typeof obj[i] == 'object') {
objects = objects.concat(getObjects(obj[i], key, val));
} else if (i == key && obj[key] == val) {
objects.push(obj);
}
}
return objects;
}
Use like so:像这样使用:
getObjects(TestObj, 'id', 'A'); // Returns an array of matching objects
This code is to select matching piece from the source.此代码用于从源中选择匹配的片段。 But what I want is to update the source object with new value and retrieve the updated source object.
但我想要的是用新值更新源对象并检索更新的源对象。
I want something like我想要类似的东西
getObjects(TestObj, 'id', 'A', 'B'); // Returns source with updated value. (ie id:'A' updated to id:'B' in the returned object)
My code我的代码
function getObjects(obj, key, val, newVal) {
var newValue = newVal;
var objects = [];
for (var i in obj) {
if (!obj.hasOwnProperty(i)) continue;
if (typeof obj[i] == 'object') {
objects = objects.concat(getObjects(obj[i], key, val));
} else if (i == key && obj[key] == val) {
obj[key] = 'qwe';
}
}
return obj;
}
This works if i give obj[key] = 'qwe';
如果我给
obj[key] = 'qwe';
这会起作用obj[key] = 'qwe';
but if i change the code into obj[key] = newValue;
但如果我将代码更改为
obj[key] = newValue;
its updated as undefined.其更新为未定义。
Why is that so?为什么?
You forgot to pass newValue in the nested call您忘记在嵌套调用中传递 newValue
function getObjects(obj, key, val, newVal) {
var newValue = newVal;
var objects = [];
for (var i in obj) {
if (!obj.hasOwnProperty(i)) continue;
if (typeof obj[i] == 'object') {
objects = objects.concat(getObjects(obj[i], key, val, newValue));
} else if (i == key && obj[key] == val) {
obj[key] = 'qwe';
}
}
return obj;
}
function getObjects(obj, key, val, newVal) {
for (var i in obj) {
if (!obj.hasOwnProperty(i)) continue;
if (i == key && obj[key] == val) {
obj[key] = newVal;
}
}
return obj
}
This will do the inplace update of a found value with the newValue (newVal)这将使用 newValue (newVal) 对找到的值进行就地更新
This ?这 ?
function update(obj, key, newVal) {
for(var i in obj) {
if(typeof obj[i] == 'object') {
update(obj[i], key, newVal));
} else if(i === key) {
obj[i] = newVal;
}
}
return obj;
}
you can try my solution你可以试试我的解决方案
const InsertOrUpdate = (dest, src) => {
GetValue(dest, src, [])
}
const GetValue = (dest, src, keys) => {
for (let key in src) {
let srcValue = src[key]
// Don't use push here
// The concat() method does not change the existing arrays, but returns a new array, containing the values of the joined arrays
let parentKeys = keys.concat(key)
if (typeof (srcValue) === 'object') {
GetValue(dest, srcValue, parentKeys)
} else {
SetValue(dest, parentKeys, srcValue)
}
}
}
const SetValue = (dest, keys, value) => {
if (!keys.length || keys.length === 0) {
return
}
let key = keys[0]
let childKeys = keys.slice(1)
// update
// note: null is object
if (dest[key] && typeof (dest[key]) === 'object') {
SetValue(dest[key], childKeys, value)
} else {
// insert
if (childKeys.length === 0) {
dest[key] = value
} else {
// insert parent key & continue update
dest[key] = {}
SetValue(dest[key], childKeys, value)
}
}
}
I tried using the selected solution above, but it would update every row with the same value.我尝试使用上面选择的解决方案,但它会用相同的值更新每一行。 So I added a way to define what record you want to update, and also a way to keep track of the current record ID once you've already looped past it.
因此,我添加了一种方法来定义您要更新的记录,以及一种在您循环过去后跟踪当前记录 ID 的方法。
function getObjects(obj, rowId, key, val, newVal, rId) {
var objects = [];
for (var i in obj) {
if(obj[i].id !== undefined) rId = obj[i].id;
if (!obj.hasOwnProperty(i)) continue;
if (typeof obj[i] == 'object') {
objects = objects.concat(this.updateObject(obj[i], rowId, key, val, newVal, rId));
} else if (i == key && obj[key] == val) {
if(rId == rowId) obj[key] = newVal;
}
}
return obj;
}
Take a look at object-scan .看看对象扫描。 We use it for a lot of data processing now.
我们现在使用它进行大量数据处理。 For us it makes the code much more maintainable, just takes a moment to wrap your head around it.
对我们来说,它使代码更易于维护,只需花一点时间来了解它。 Here is how you could answer your question
这是你如何回答你的问题
// const objectScan = require('object-scan'); const update = (data, needle, from, to) => objectScan([needle], { abort: true, rtn: 'bool', filterFn: ({ value, parent, property }) => { if (value === from) { parent[property] = to; return true; } return false; } })(data); // ------------------------------- const TestObj = { Categories: [{ Products: [{ id: 'a01', name: 'Pine', description: 'Short description of pine.' }, { id: 'a02', name: 'Birch', description: 'Short description of birch.' }, { id: 'a03', name: 'Poplar', description: 'Short description of poplar.' }], id: 'A', title: 'Cheap', description: 'Short description of category A.' }, { Product: [{ id: 'b01', name: 'Maple', description: 'Short description of maple.' }, { id: 'b02', name: 'Oak', description: 'Short description of oak.' }, { id: 'b03', name: 'Bamboo', description: 'Short description of bamboo.' }], id: 'B', title: 'Moderate', description: 'Short description of category B.' }] }; console.log(update(TestObj, '**.id', 'A', 'B')); // => true console.log(TestObj); // => { Categories: [ { Products: [ { id: 'a01', name: 'Pine', description: 'Short description of pine.' }, { id: 'a02', name: 'Birch', description: 'Short description of birch.' }, { id: 'a03', name: 'Poplar', description: 'Short description of poplar.' } ], id: 'B', title: 'Cheap', description: 'Short description of category A.' }, { Product: [ { id: 'b01', name: 'Maple', description: 'Short description of maple.' }, { id: 'b02', name: 'Oak', description: 'Short description of oak.' }, { id: 'b03', name: 'Bamboo', description: 'Short description of bamboo.' } ], id: 'B', title: 'Moderate', description: 'Short description of category B.' } ] }
.as-console-wrapper {max-height: 100% !important; top: 0}
<script src="https://bundle.run/object-scan@13.8.0"></script>
Disclaimer : I'm the author of object-scan免责声明:我是对象扫描的作者
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