带有变量的命令行，不起作用

Question

I have a script that uses awk with parameters but I can't find the right syntax to make it functionnal. May be could you help me ? (under osx, terminal, zsh, command line)

I get a variable who is the path name (it's a awk result)

path_dir="/picture/dir/'

After, I ask this:

awk -F"/" '{print $2}' $path_dir

But it doesn't work. I get:

cant' open file $path_dir

My goal is to do this:

dir_name=awk -F "/" '{print $2}' $path_dir

Then, to use

$dir_name

But first, awk can't read my $path_dir

Any idea ?

Thank you

Answer 1

try this:

dir_name=$(awk -F'/' '{print $2}' <<<$path_dir)

this should assign dir_name with picture

Answer 2

尝试：

dir_name=`awk -F "/" '{print $2}' $path_dir`