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C ++中的简单文本菜单

[英]Simple text menu in C++

I am writing a silly little app in C++ to test one of my libraries. 我正在用C ++写一个愚蠢的小应用程序来测试我的一个库。 I would like the app to display a list of commands to the user, allow the user to type a command, and then execute the action associated with that command. 我希望该应用程序向用户显示命令列表,允许用户键入命令,然后执行与该命令关联的操作。 Sounds simple enough. 听起来很简单。 In C# I would end up writing a list/map of commands like so: 在C#中,我最终将像这样编写命令列表/映射:

    class MenuItem
    {
        public MenuItem(string cmd, string desc, Action action)
        {
            Command = cmd;
            Description = desc;
            Action = action;
        }

        public string Command { get; private set; }
        public string Description { get; private set; }
        public Action Action { get; private set; }
    }

    static void Main(string[] args)
    {
        var items = new List<MenuItem>();

        items.Add(new MenuItem(
            "add",
            "Adds 1 and 2",
            ()=> Console.WriteLine(1+2)));
    }

Any suggestions on how to achieve this in C++? 关于如何在C ++中实现这一点的任何建议? I don't really want to define separate classes/functions for each command. 我真的不想为每个命令定义单独的类/函数。 I can use Boost, but not TR1. 我可以使用Boost,但不能使用TR1。

A very common technique is to use function pointers, or boost::function, indexed by the item name, or by having a vector of them and indexing by the item index for this job. 一种非常常见的技术是使用函数指针或boost :: function,通过项目名称进行索引,或者通过使用它们的向量并通过此项工作的项目索引进行索引。 Simple example using the item name: 使用项目名称的简单示例:

void exit_me(); /* exits the program */
void help(); /* displays help */

std::map< std::string, boost::function<void()> > menu;
menu["exit"] = &exit_me;
menu["help"] = &help;

std::string choice;
for(;;) {
    std::cout << "Please choose: \n";
    std::map<std::string, boost::function<void()> >::iterator it = menu.begin();
    while(it != menu.end()) {
        std::cout << (it++)->first << std::endl;
    }

    std::cin >> choice;
    if(menu.find(choice) == menu.end()) {
        /* item isn't found */
        continue; /* next round */
    }   

    menu[choice](); /* executes the function */
}

C++ doesn't have a lambda feature yet, so you really have to use functions for this task, sadly. C ++还没有lambda功能,因此遗憾的是,您确实必须使用函数来完成此任务。 You can use boost::lambda, but note it is just simulating lambdas, and nowhere near as powerful as a native solution: 您可以使用boost :: lambda,但是请注意,它只是在模拟lambdas,远没有本机解决方案强大:

menu["help"] = cout << constant("This is my little program, you can use it really nicely");

Note the use of constant(...), since otherwise boost::lambda wouldn't notice that this is supposed to be a lambda expression: The compiler would try to output the string using std::cout, and assign the result (an std::ostream reference) to menu["help"]. 请注意使用constant(...),因为否则boost :: lambda不会注意到这应该是lambda表达式:编译器将尝试使用std :: cout输出字符串,并分配结果(菜单[“ help”]的std :: ostream引用)。 You can still use boost::function, since it will accept everything returning void and taking no arguments - including function objects, which is what boost::lambda creates. 您仍然可以使用boost :: function,因为它将接受所有返回void并且不带参数的东西-包括函数对象,这就是boost :: lambda创建的。

If you really don't want separate functions or boost::lambda, you can just take print out a vector of the item names, and then switch on the item number given by the user. 如果您确实不想要单独的功能或boost :: lambda,则只需打印出项目名称的向量,然后switch用户指定的项目编号即可。 This is probably the easiest and most straight forward way of doing it. 这可能是最简单,最直接的方法。

Why not just port the C# code to C++? 为什么不只是将C#代码移植到C ++? There's a little work to be done, but something like this should get most of your work done: 有一些工作要做,但是这样的事情应该可以完成大部分工作:

using std::string;
class MenuItem    
{        
    public:
        MenuItem(string cmd, string desc, boost::function<bool()> action):Command(cmd),
                                                                          Description(desc),
                                                                          Action(action) 
        {}
        boost::function<bool()> GetAction() { return Action; }
        string GetDescription() { return Description; }
        string GetCommand() { return Command; }
    private:
        string Command;
        string Description;
        boost::function<bool()> Action;
}

With that defined, your main() can use a std::list, and use a simple while() loop that checks the exit value of the MenuItem's Action to determine if it should exit. 定义好之后,您的main()可以使用std :: list,并使用一个简单的while()循环来检查MenuItem的Action的退出值,以确定是否应退出。

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