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映射枚举和字符串

[英]Mapping enum and string

I have an array say arr[3] and I used enums to index into the array say 我有一个数组说arr[3] ,我用枚举索引到数组说

typedef enum {
ABC,
DEF,
XYZ
}INDEX;

I store values in the array as ar[ABC] = 100 and so on... Now I have a file having the strings as xyZ = 2, dEF = 3, abc = 4 . 我在数组中将值存储为ar[ABC] = 100 ,依此类推...现在我有一个文件,其字符串为xyZ = 2, dEF = 3, abc = 4 I parse this file and check for the string. 我解析此文件并检查字符串。 If the string is xyZ then I need to store the value in the array arr[XYZ] and so on.. I am struck in mapping the string with enums.How will I know the enum index with the strings in file. 如果字符串是xyZ那么我需要将值存储在数组arr[XYZ] ,依此类推。.在使用enums映射字符串时,我感到很震惊。我怎么知道文件中包含字符串的enum索引。 Any ideas please. 有什么想法。 Hope I am clear.Thanks 希望我清楚。谢谢

You can take 'a' as index 0 您可以将'a'作为索引0

#include <stdio.h>

typedef enum {
    ABC,
    DEF,
    GHI,
    JKL,
    MNO,
    PQR,
    STU,
    VWX,
    YZ,
    N
} INDEX;

#define GET_INDEX(x) (((x) - 'a') / 3)

int main(void)
{
    char *s[] = {"abc", "def", "mno", "def"};
    int i, arr[N] = {0};

    for (i = 0; i < 4; i++) {
        arr[GET_INDEX(s[i][0])] += 1;
    }
    for (i = 0; i < N; i++) {
        printf("arr[%d]=%d\n", i, arr[i]);
    }
    return 0;
}

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