我在重新分配python中的变量时遇到问题

Question

I am trying to create a text adventure game in python. I am using randint to create a number between 0 and 2 and when I use an if statement to take the random number and assign the biome variable to a biome type it instead takes the original version of the variable and uses that as the biome.

#Defines game()
print ('''You are in a %s biome.'''%(biome))
biome='placeholder'
import random
trees=random.randint(0,50)
biomes=random.randint(0,2)
animals=random.randint(0,3)
wolves=random.randint(0,5)
if biomes == "0":
    biome='Forest'

if biomes == "1":
    biome='Taiga'

if biomes == "2":
    biome='Mountain'

print ('''You are in a %s biome.'''%(biome))

Answer 1

biomes is int value. "0" is string value.

Both values never can be equal.

>>> 0 == "0"
False

Use int literal.

if biomes == 0:
    biome = 'Forest'
elif biomes == 1:
    biome = 'Taiga'
elif biomes == 2: # else
    biome = 'Mountain'

I recommed you to use random.choice as other suggested. Simple, eaiser to read.

>>> random.choice(['Forest', 'Taiga', 'Mountain'])
'Mountain'
>>> random.choice(['Forest', 'Taiga', 'Mountain'])
'Mountain'
>>> random.choice(['Forest', 'Taiga', 'Mountain'])
'Taiga'

Answer 2

random.randint(...) returns an integer. You are comparing the value to a string here.

>>> type(randint(0, 2))
<type 'int'>

Your if statements should be rewritten as -

if biomes == 0:
    biome='Forest'
elif biomes == 1:
    biome='Taiga'
else:
    biome='Mountain'

PS -- You don't need three if statements, since, if the value is 0 , it can never be 1 or 2 , so no need to check the conditions. You can use an if-elif-else construct instead.

Answer 3

Here's a more understandable way:

from random import choice
biomes = ['Forest', 'Tiaga', 'Mountain']
biome = choice(biomes)

Then if the number of biomes increases, or decreases, you don't have to worry about updating the range for the random number, and not quite getting your if statements right...

Answer 4

You need to compare to 0 rather than the string value "0" as in if biome == 0:

However, this can be simplified with random.choice to select a biome randomly from a list.

biome = random.choice(['Forest', 'Taiga', 'Mountain'])

and eliminate your if s altogether.

Answer 5

我认为您应该尝试使用if语句biome == 1代替biome ==“ 1”，并且对biome == 2和biome == 3相同。

Answer 6

That's because you are comparing an integer value to a string (which will never equal). This will work:

import random
trees=random.randint(0,50)
biomes=random.randint(0,2)
animals=random.randint(0,3)
wolves=random.randint(0,5)

# Compare biomes (which is an integer) to another integer
if biomes == 0:
    biome='Forest'

# Use elif for multiple comparisons like that
elif biomes == 1:
    biome='Taiga'

# Use an else here because the only other option is 2
else:
    biome='Mountain'

print ('''You are in a %s biome.'''%(biome))

Note also I removed the first and second lines of your script. The first would have blown up because biome isn't defined yet and the second does nothing.