[英]Laravel 4 Public Functions
I've got a question. 我有一个问题。 I made a function that says if 'type' (a column in my database) is equal to five, it'll display buttons that others can't view.
我创建了一个函数,说明如果'type'(我的数据库中的一列)等于五,它将显示其他人无法查看的按钮。 The problem is when I log out or log into a user that doesn't have type equals to five, it displays an error.
问题是当我注销或登录没有类型等于5的用户时,它会显示错误。 How could I do this in a function?
我怎么能在一个函数中做到这一点? I tried various things, but it always displays errors.
我尝试了各种各样的东西,但它总是显示错误。 Here's my method...
这是我的方法......
<?php
public function get_dash()
{
$roles = Auth::user()->type;
if ($roles == '5') {
return View::make('admin.dash')->with('roles', $roles);
} else {
return Redirect::to('news/index')
->with('danger', 'You either have insufficient permissions
to access this page or your user credentials
are not refreshed.');
}
}
I basically want it so that if no type equals to five in an account, or when I log out it'll load normally... 我基本上想要它,以便如果一个帐户中没有类型等于五,或者当我注销它时,它将正常加载...
return View::make('news/index');
When a user is not authenticated, you have no access to ´Auth::user()´, so you need something like this: 如果用户未经过身份验证,则您无权访问'User :: user()',因此您需要以下内容:
public function get_index()
{
if( ! Auth::guest() )
{
$roles = Auth::user()->type;
return View::make('aac.index')
->with('newss', News::all())
->with('roles', $roles);
}
else
{
return Redirect::to('login');
}
}
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