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使用Boost :: Python获取指向Python实例的c ++指针

[英]Get a c++ pointer to a Python instance using Boost::Python

I am working on embedding Python inside of a C++ application. 我正在努力将Python嵌入到C ++应用程序中。 When I create a new object in Python, I want to be able to store a reference to that Object in my C++ application, so that I can later call methods on that object. 当我在Python中创建一个新对象时,我希望能够在我的C ++应用程序中存储对该Object的引用,以便稍后可以调用该对象上的方法。 What's the recommended way of doing this? 建议的方法是什么?

For Example, I would like to be able to do something like this : 例如,我希望能够做到这样的事情:

Entity.py Entity.py

class Entity:
    def getPointer(self)
        return pointertoSelf;

Manager.cpp Manager.cpp

Py_Initialize();
PyRun_SimpleString("import Entity");
PyRun_SimpleString("entity = Entity.Entity()");

pointerToPythonObj* = somehowGetPointerToObj("entity");

The recommended way is to query into the namespace in which the entity object was created, then store a handle to the entity object as a boost::python::object . 建议的方法是查询创建entity对象的命名空间,然后将entity对象的句柄存储为boost::python::object When interacting with Python objects from C++, it is best to use boost::python::object whenever possible, as it provides a high-level notation that acts much like a Python variable. 当与C ++中的Python对象进行交互时,最好尽可能使用boost::python::object ,因为它提供了一个与Python变量非常相似的高级表示法。 Additionally, it provides the appropriate reference counting to manage the lifetime of the Python object. 此外,它还提供适当的引用计数来管理Python对象的生命周期。 For example, storing a raw pointer (ie pointerToPythonObj* ) would not extend the life of the Python object; 例如,存储原始指针(即pointerToPythonObj* )不会延长Python对象的生命周期; if the Python object was garbage collected from within the interpreter, then pointerToPythonObj would be a dangling pointer. 如果Python对象是从解释器中收集的垃圾,那么pointerToPythonObj将是一个悬空指针。


Here is an example demonstrating this: 这是一个证明这一点的例子:

Entity.py: Entity.py:

class Entity:
    def action(self):
        print "in Entity::action"

main.cpp: main.cpp中:

#include <boost/python.hpp>

int main()
{
  namespace python = boost::python;
  try
  {
    Py_Initialize(); // Start interpreter.

    // Create the __main__ module.
    python::object main = python::import("__main__");
    python::object main_namespace = main.attr("__dict__");

    // Import Entity.py, and instantiate an Entity object in the
    // global namespace.  PyRun_SimpleString could also be used,
    // as it will default to running within and creating 
    // __main__'s namespace.
    exec(
        "import Entity\n"
        "entity = Entity.Entity()\n"
      , main_namespace
    );

    // Obtain a handle to the entity object created from the previous
    // exec.
    python::object entity = main_namespace["entity"];
    // Invoke the action method on the entity.
    entity.attr("action")();
  }
  catch (const python::error_already_set&)
  {
    PyErr_Print();
  }
}

Running the above program results in the following output: 运行以上程序会产生以下输出:

in Entity::action

If Entity.py is failing to be imported, then it may require adding its containing directory to the PYTHONPATH environment variable. 如果无法导入Entity.py ,则可能需要将其包含的目录添加到PYTHONPATH环境变量中。

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