杰森不使用angular.js

Question

I'm trying to get forecast information from an external domain, which doesn't seem to work yet. Both Angular and jQuery are loaded, but nothing shows up in HTML. Chrome doesn't report an error message either.

        var currentCityread = "Eindhoven";
        var api1 = 'http://api.openweathermap.org/data/2.5/forecast/daily?q='+currentCityread+'&cnt=10&mode=json&units=metric&APPID=000000000000000&callback=?';
        var api2 = 'http://api.openweathermap.org/data/2.5/weather?q='+currentCityread+'&mode=json&units=metric&APPID=000000000000000&callback=?'
        function ReadJson($scope) {
            $.ajax({
              dataType: "json",
              url: api1,
              }).done(function (output) {
                $scope.jsonTotal = output.list[0].temp.day+output.list[1].temp.day+output.list[2].temp.day+output.list[3].temp.day+output.list[4].temp.day+output.list[5].temp.day+output.list[6].temp.day+output.list[7].temp.day+output.list[8].temp.day+output.list[9].temp.day;
                $scope.jsonCalcu = Math.round($scope.jsonTotal / 10);
                $scope.jsonCurrent = Math.round(output.list[0].temp.day);
                $scope.jsonCurrent2 = Math.round(output.list[1].temp.day);
                $scope.jsonCurrenticon2 = output.list[1].weather[0].icon;
                $scope.jsonCurrent3 = Math.round(output.list[2].temp.day);
                $scope.jsonCurrenticon3 = output.list[2].weather[0].icon;
            });
            $.ajax({
              dataType: "json",
              url: api2,
              }).done(function (outputcurrent) {
                $scope.jsonCurrenticon = outputcurrent.weather[0].icon;
            });
        }

Answer 1

Since you are updating the scope after a callback which is outside the angular execution context, you need to use $scope.$apply() .

But as others have mentioned in their comments $http can be used, with JSONP as the request is cross domain.

Answer 2

I think same-origin policy forbids you from performing cross-domain query. What you can do is to perform the query on the server side, and return the result to the browser. Another workaround is to use jsonp. But it is not recommended due to its insecure nature.