Java VS C＃中的intBitsToFloat方法？

Question

I'm getting the wrong number when converting bits to float in C#.

Let's use this bit number= 1065324597

In Java , if I want to convert from bits to float I would use intBitsToFloat method

int  intbits= 1065324597;
System.out.println(Float.intBitsToFloat(intbits));

Output: 0.9982942 which the correct output the I want to get in C#

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However, in C# I used

int  intbits= 1065324597;
Console.WriteLine((float)intbits);

Output: 1.065325E+09 Wrong!!

My question is how would you convert inbitsToFloat in C#?

My attempt: I looked to the documentation here http://msdn.microsoft.com/en-us/library/aa987800(v=vs.80).aspx but I still have the same trouble

Answer 1

Just casting is an entirely different operation. You need BitConverter.ToSingle(byte[], int) having converted the int to a byte array - and possibly reversed the order, based on the endianness you want. (EDIT: Probably no need for this, as the same endianness is used for both conversions; any unwanted endianness will just fix itself.) There's BitConverter.DoubleToInt64Bits for double , but no direct float equivalent.

Sample code:

int x = 1065324597;
byte[] bytes = BitConverter.GetBytes(x);
float f = BitConverter.ToSingle(bytes, 0);
Console.WriteLine(f);

Answer 2

我想在乔恩·斯凯特说的话之上加上，对于大浮点数，如果您不希望“ E +”输出，也应该这样做：

intbits.ToString("N0");

Answer 3

Just try this...

var myBytes = BitConverter.GetBytes(1065324597);
var mySingle = BitConverter.ToSingle(myBytes,0);

The BitConverter.GetBytes converts your integer into a four byte array. Then BitConverter.ToSingle converts your array into a float(single).