通过合并jstl中两个大小不等的列表以表格格式显示

Question

Sorry if my question is not clear. Let me explain - I have two lists, model.List1 & model.List2 of unequal sizes . However, I still need to display model.List2 in such a way that, the list elements appear under the Territory column. How do I merge these two lists? I somehow need to iterate List2 within the block marked with ** **

Edit: As you can see, List 1 has five entries while list 2 has only 3 entries. If I iterate my second list within my first list, for each Iteration of List1, I am getting all the 3 Territories (Please see SEC1). This is not what I want..

<table>
<thead>
 **<tr>**
  <th>User</th>
  <th>Title</th>
  <th>Role</th>
  <th>Territory</th>

  **</tr>**
</thead>
<tbody>
<c:forEach items="${model.List1}" var="list">
<tr>
<td>${list.name} </td>
<td>${list.title} </td>
<td>${list.role} </td>
</tr>
</c:forEach>



<c:forEach items="${model.List2}" var="terr">
  <td>${terr}</td>      
</c:forEach> 
</tbody>

</table>

Current Output:

User     Title  Role  Territory


user1    Lead   Lead


Territory1

Desired Output:

User     Title  Role      Territory


user1    Lead   Lead      Territory1

user2    Lead2  Lead2     Territory2

user3    Lead3  Lead3     Territory3

User4    Lead4  Lead4

User5    Lead5  Lead5     

SEC1 - This is not what I want

User     Title  Role      Territory


user1    Lead   Lead      Territory1 Territory2 Territory3

user2    Lead2   Lead2    Territory1 Territory2 Territory3

user3    Lead3   Lead3    Territory1 Territory2 Territory3

Answer 1

You could do it like this

<table>
<c:forEach items="${ list1 }" var="item" varStatus="status1"> 
  <tr>
    <td>${ item.name }</td>

    <td>
      <c:if test="${ status1.index lt fn:length(list2) }">
        ${ list2[status1.index].name }
      </c:if> 
    </td>      
  </tr>
</c:forEach>
</table>

The c:if checks, if the 2nd list is large enough.

Related: forEach's varStatus variable