如何循环显示Javascript多维数组

Question

I have a testing search software and it stores the data in a multidimensional array. I can return the whole database but cannot return just one value. I'm trying to figure out how to return one section as a multidimensional array. Otherwise it just repeats the passed value across the display. While De-bugging it i can see the complete array stored as an argument but am having trouble figuring out how to loop through that array to display correctly. You may need to view the source to understand better. If you enter lets say 439023483 and click search by ISBN button, you will see my issue. The show all button works fine. Anything pointing me in the right direction would be greatly appreciated and thank you in advance.

Here is a link to the testing source: http://mdhmotors.com/jstesting/test.html

Here is the part of the code that I'm stuck on:

function searchByISBN(isbn)
{
    var isbn = document.getElementById('isbn').value;
    showBooks(getBookByIsbn(isbn));

}
function getBookByIsbn(isbn)
{
  var foundBook = null;
  for (b in BookStore)
  {
      var book = BookStore[b];
      if (book[ISBN] == isbn)
      {
          foundBook = new Array(book[ISBN], book[TITLE], book[AUTHOR], book[PUBLISHER], book[WS_PRICE], book[RET_PRICE], book[QUANTITY]);
          break;
      }
  }
  return foundBook; 
}

/*display search results*/
function showBooks(searchResults)
{
  //clearDisplayTable();
  if (searchResults == null)
  {
      return;
  }
  var row, cell, displayTable, tableHeader, tableTitle;
  displayTable = document.createElement('table');
  displayTable.className = "mytable";
  tableBody = document.createElement('tbody');
  row = document.createElement('tr');
  tableHeader = document.createElement('th');
  tableHeader.appendChild(document.createTextNode("Book Store Inventory"));
  tableHeader.setAttribute('colSpan', 8);
  tableHeader.setAttribute('style', 'font-size: 22px');
  row.appendChild(tableHeader);
  tableBody.appendChild(row);

 row = document.createElement('tr');
 columnName = document.createElement('th');
 columnName.appendChild(document.createTextNode("#"));
 row.appendChild(columnName);

 columnName = document.createElement('th');
 columnName.appendChild(document.createTextNode("Isbn"));
 row.appendChild(columnName);

 columnName = document.createElement('th');
 columnName.appendChild(document.createTextNode("Title"));
 row.appendChild(columnName);

 columnName = document.createElement('th');
 columnName.appendChild(document.createTextNode("Author"));
 ow.appendChild(columnName);

 columnName = document.createElement('th');
 columnName.appendChild(document.createTextNode("Publisher"));
 row.appendChild(columnName);

 columnName = document.createElement('th');
 columnName.appendChild(document.createTextNode("W/S"));
 row.appendChild(columnName);

 columnName = document.createElement('th');
 columnName.appendChild(document.createTextNode("Retail"));
 row.appendChild(columnName);

 columnName = document.createElement('th');
 columnName.appendChild(document.createTextNode("Qty"));
 row.appendChild(columnName);
 tableBody.appendChild(row);

  var count = 0;
  for (b in searchResults)
  {
    row = document.createElement('tr');
    book = searchResults[b];
    var data = new Array(++count, book[ISBN], book[TITLE], book[AUTHOR], book[PUBLISHER], book[WS_PRICE], book[RET_PRICE], book[QUANTITY]);
      for (var index = 0; index < 8; index++)
      {
          cell = document.createElement('td');
          cellText = document.createTextNode(data[index]);

          if (index == 0)
          cell.setAttribute('style', 'text-align: right');
          cell.appendChild(cellText);
          row.appendChild(cell);
      }
   tableBody.appendChild(row);
   }
displayTable.appendChild(tableBody);
bookResults.appendChild(displayTable);
}

Answer 1

To return a value in a multidimensional array: array[n][m] is the mth element of the nth row. To do this for every element, use embedded for-loops:

for (var i = 0; i < array.length; i++){
    for (var j = 0; j < array[i].length; j++){
        console.log(array[i][j]);

Answer 2

Using jQuery - but easily adaptable to pure JS:

var my_multi_dimensional_array = ["a", "b", "c", ["d", "e", "f"], "g", ["h", ["i"],
    ["j", "k"], "l", ["m", ["n", "o", [
        [
            ["p"], "q"]
    ]]]
]];

(function walkies(arr, path, callback, root) {
    $.each(arr, function (i, v) {
        //push index onto path stack
        path.push(i);
        var recurseable = ($.isArray(v) || $.isPlainObject(v)) ;
        var recurse = callback.call(v, !recurseable, v, path, i, root || arr) && recurseable;

        //call callback and continue recursing this node until callback returns false
        if ( recurse) {
            walkies(v, path, callback, root || arr);
        }

        //pop last index off path stack
        path.pop();
    });
}(my_multi_dimensional_array, [], function (isLeaf, node, path, index, root) {
    if( isLeaf ){
        console.log( "[" + path.join("],[") + "]=" + node );
    }
    return true;
}));

jsFiddle