[英]Counting Distinct values from Sql Table
Following is a view of my table... 以下是我桌子的视图...
I am getting a hard time in getting desired result from a query. 我很难从查询中获得想要的结果。
My requirement looks like below image 我的要求如下图所示
It should be conditioned as follows -- 1)Within start date and end date. 它应满足以下条件:1)在开始日期和结束日期之内。
2)No as Pending . 2)没有待定。
3)Yes as Completed. 3)是的。
4)No+Yes as Total. 4)否+是总计。
5)Based On only one survey Type. 5)仅基于一种调查类型。
This is what i have tried and got result for above mentioned 1 to 4 condition , but how to impliment 5 condition ? 这是我为上面提到的1到4条件尝试过的结果,但是如何隐含5条件呢?
SELECT DISTINCT Userid
,CASE
WHEN [YES] IS NULL
THEN 0
ELSE [YES]
END AS Completed
,CASE
WHEN [NO] IS NULL
THEN 0
ELSE [NO]
END AS Pending
,(
CASE
WHEN [YES] IS NULL
THEN 0
ELSE [YES]
END + CASE
WHEN [NO] IS NULL
THEN 0
ELSE [NO]
END
) AS Total
FROM (SELECT DISTINCT Userid
,SurveyStatus
,COUNT(ParcelId) AS cnt
FROM ParcelAllocationsurvivor
WHERE DateAllocated >= '2013-08-01'
AND DateAllocated <= '2013-08-07'
GROUP BY Userid
,SurveyStatus
) AS p
PIVOT(max(cnt) FOR surveystatus IN ([YES],[NO])) AS pvt
ORDER BY Userid
Can anybody help me out in it. 有人可以帮我吗?
thanks in advance//// 提前致谢////
You would add a where
clause into the subquery: 您可以在子查询中添加
where
子句:
SELECT Userid, (case when [YES] is null then 0 else [YES] end) as Completed,
(case when [NO] is null then 0 else [NO] end) as Pending,
(case when [YES] is null then 0 else [YES] end +
case when [NO] is null then 0 else [NO] end
) as Total
FROM (SELECT Userid, SurveyStatus, COUNT(ParcelId) as cnt
FROM ParcelAllocationsurvivor
WHERE DateAllocated >= '2013-08-01' and DateAllocated <='2013-08-07' and
SurveyType = 'Survey1'
group by Userid, SurveyStatus
) AS p
PIVOT(max(cnt) FOR surveystatus IN([YES],[NO])) AS pvt order by Userid;
By the way, the select distinct
are redundant. 顺便说一句,
select distinct
是多余的。 You do not need them for this query. 您不需要此查询。
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.