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使用javascript从css中检索背景图像而不使用它的ID

[英]retrieve background image from css using javascript without using it's ID

I've looked around and it's been hard to find a thread that does what I want it to do. 我环顾四周,很难找到一个能做我想做的事情的线程。 As far as I am concerned, I don't even know if it's possible. 就我而言,我甚至不知道是否可能。 What I am looking to do is to retrieve the background image file name (especially if it is a link) when it is click. 我想要做的是在点击时检索背景图像文件名(特别是如果它是一个链接)。 I have a script that logs all click but the last piece I need is the background-image name (file-path with name would even do) stored in the CSS file. 我有一个记录所有点击的脚本,但我需要的最后一块是存储在CSS文件中的背景图像名称(文件路径,名称甚至可以)。 Anyone have an idea or a solution as to how this can be done without using a div or class? 任何人都有一个想法或解决方案,如何在不使用div或类的情况下完成此操作? Here's what I have right now: 这就是我现在所拥有的:

JavaScript & HTML JavaScript和HTML

<script type="text/javascript">
var arrayWithElements = new Array(); //,replaytimer;

document.onclick = clickListener;

function clickListener(e)
{
var clickedElement=(window.event)
                    ? window.event.srcElement
                    : e.target,
    tags=document.getElementsByTagName(clickedElement.tagName);

for(var i=0;i<tags.length;++i)
{
  if(tags[i]==clickedElement)
  {
    if(clickedElement.tagName=="A")
    {
      arrayWithElements.push({tag:clickedElement.tagName,index:i});
      console.log(clickedElement.baseURI,clickedElement.href,clickedElement.innerText,document.location.href,document.images.href);
    }
    if(clickedElement.tagName=="IMG")
    {
      arrayWithElements.push({tag:clickedElement.tagName,index:i});
      console.log(clickedElement.baseURI,clickedElement.parentNode.href,clickedElement.innerText,document.location.href,document.getElementsById(element).src);
    }
    if(clickedElement.tagName=="DIV")
    {
      arrayWithElements.push({tag:clickedElement.tagName,index:i});
      console.log(clickedElement.baseURI,clickedElement.parentNode.href,clickedElement.innerText,document.location.href,document.getElementsById(element).src);
    }
    if(clickedElement.tagName=="CLASS")
    {
      arrayWithElements.push({tag:clickedElement.tagName,index:i});
      console.log(clickedElement.baseURI,clickedElement.parentNode.href,clickedElement.innerText,document.location.href,document.getElementsById(element).src);
        }
      }
    }
  }
</script>
</head>

<a id="1" href="#">trial1</a>
<a id="2" href="http://www.google.com" target="blank">google</a>
<a id="3" href="http://www.google.com">google</a>
<a id="4" href="http://www.google.com" target="_blank"><img id="image" src="untitled.jpg"/></a>
<a id="5" href="trial.html">
<input type="text" id="text-test"/>
<a href="http://www.google.com"><div id="image-link"></div></a>

CSS: CSS:

#image-link {
        background-image:url('untitled.jpg');
        width: 50px;
        height:50px;
        border: 1px solid #000000;
}

This is a test file that will be converted for use in the near future. 这是一个测试文件,将在不久的将来转换使用。 Thanks 谢谢

在较新的浏览器上,您可以使用window.getComputedStyle(clickedElement)来查找背景图像属性。

As per your code, just the filename or the path using JQuery in all browsers: 根据您的代码,只需在所有浏览器中使用JQuery的文件名或路径:

var withId = $("#image-link").css("background-image").split('(')[1].split(')'),
    withoutId = $("img").attr("src");

    // with id and css file
    console.log(withId[0]);
    // without id and inline style
    console.log(withoutId);

Yes, as Alnitak says, use getComputedStyle , but for compatibility with more browsers check out this other question: 是的,正如Alnitak所说,使用getComputedStyle ,但为了与更多浏览器兼容,请查看另一个问题:

Get element CSS property (width/height) value as it was set (in percent/em/px/etc) 获取设置的元素CSS属性(宽度/高度)值(以百分比/ em / px /等为单位)


Note: I would love to be able to comment on another user's good answer instead of posting my own that is pretty much the same but with a little additional info. 注意:我希望能够评论另一个用户的好答案,而不是发布我自己的,几乎相同,但有一些额外的信息。 Unfortunately, I cannot because stackoverflow doesn't permit this for a user with less than 50 rep. 不幸的是,我不能,因为stackoverflow不允许小于50代表的用户。 So I have to post it like this instead. 所以我必须这样发布它。

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