多个下拉列值插入单行而不是多行
[英]Multiple dropdown values inserting in a single row not in multiple row
问题描述
In this code when i selected multiple values from dropdown it is stoing in a single row but i like to apply value in each row so please anybody help me. 
在此代码中，当我从下拉列表中选择多个值时，它会在一行中存储，但我想在每行中应用值，所以请任何人帮助我。 Actual result: 实际结果：
id game
1. cricket,football,tennis
Expecting result: 期待结果：
id game
1 cricket
2 football
code - 代码 -
<html>
<body>
<?php
if(isset($_POST['submit']))
{
$query=mysql_connect('localhost','root','');
mysql_select_db("freeze",$query);
$choice=$_POST['game'];
$choice1=implode(',',$choice);
mysql_query("insert into tb values('','$choice1')");
}
?>
<form method="post" action="multipleselect.php">
Select your favourite game:<br/>
<select name="game[]" multiple="multiple">
<option>Football</option>
<option>Volleyball</option>
<option>Badminton</option>
<option>Cricket</option>
<option>Cricket1</option>
<option>Cricket2</option>
<option>Cricket3</option>
<option>Cricket34</option>
</select>
<input type="submit" name="submit">
</form>
</body>
</html>
4 个解决方案
解决方案1
3 2013-08-10 05:13:09
First of all, please don't use mysql_* as it's deprecated, use mysqli_ or PDO instead. 首先，请不要使用mysql_*因为它已被弃用，请改用mysqli_或PDO 。
now if you just want the values of options then do it like this 现在，如果您只想要选项的值，那么就这样做
<select name="game[]" multiple="multiple">
<option value="1">Football</option>
<option value="2">Volleyball</option>
...
</select>
this way it'll give you 1,2,.... . 这样它会给你1,2,.... Hope that's what you're looking for. 希望这就是你要找的东西。
and if you're looking for query like this 如果你正在寻找像这样的查询
INSERT INTO tb (`game`) VALUES ('Football'),('Volleyball')
assuming that id field is auto-incremented, then change the code as follows: 假设id字段是自动递增的，那么更改代码如下：
html code HTML代码
<select name="game[]" multiple="multiple">
<option>Football</option>
<option>Volleyball</option>
...
</select>
php code PHP代码
$choice=$_POST['game'];
$sql = "INSERT INTO tb (`game`) VALUES ";
$sqlValues= null;
foreach($choice as $ch) {
$sqlValues .= "('$ch')," ;
}
$sql.=rtrim($sqlValues, ",");
echo $sql;
this way you could get 这样你就可以得到
id game
1 cricket
2 football
解决方案2
1 已采纳 2013-08-10 05:14:02
It is inserting them all in 1 row, because you are imploding your $_POST['game'] 它将它们全部插入一行，因为你正在破坏你的$_POST['game']
$choice=$_POST['game'];
$choice1=implode(',',$choice);
mysql_query("insert into tb values('','$choice1')");
You need to loop over each $_POST['game'] value 你需要遍历每个$_POST['game']值
foreach($_POST['game'] as $choice){
mysql_query("insert into tb values('','$choice')");
}
note, your query is open to SQL injection, make sure to sanitize your data before inserting into your db. 请注意，您的查询对SQL注入是开放的，请确保在插入数据库之前清理数据。 Also, mysql_* are deprecated, so you should update to mysqli or PDO - http://php.net/manual/en/mysqlinfo.api.choosing.php 此外，不推荐使用mysql_* ，因此您应该更新到mysqli或PDO - http://php.net/manual/en/mysqlinfo.api.choosing.php
解决方案3
0 2013-08-10 05:11:22
Are there any error messages being displayed? 是否显示任何错误消息？ Insert the following code just before the mysql_query statement: 在mysql_query语句之前插入以下代码：
echo "insert into tb values('','$choice1')";
what is being displayed? 什么是显示？
解决方案4
0 2013-08-10 05:17:32
<?php
if(isset($_POST['submit']))
{
$query=mysql_connect('localhost','root','');
mysql_select_db("freeze",$query);
$choice=$_POST['game'];
$choice1=implode(',',$choice);
foreach($choice1 as $choice)
{
mysql_query("insert into tb values('','$choice')");
}
}
?>
You just try this code i hope it works for you. 您只需尝试此代码，我希望它适合您。 If not then please reply me. 如果没有，请回复我。
声明:本站的技术帖子网页，遵循CC BY-SA 4.0协议，如果您需要转载，请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.