[英]solaris simple bash script
I'm trying to execute this simple script in solaris. 我正在尝试在solaris中执行这个简单的脚本。 I want to sort(numeric) the filenames of the files in source directory and copy the file one by one to another directory.
我想对源目录中文件的文件名进行排序(数字化),并将文件逐个复制到另一个目录。 And, I want to print a message after copying every 100 files.
并且,我想在复制每100个文件后打印一条消息。
#!/bin/bash
count=0
for i in `ls | sort -n`
do
cp $i ../target
count = $((count+1))
if[ $count%100 -eq 0 ]
then
echo $count files copied
sleep 1
fi
done
this is not working. 这不起作用。 I tried different things after searching in net.
我在网上搜索后尝试了不同的东西。
I get errors like these - 我得到这样的错误 -
syntax error at line 8: '(' unexpected. 第8行的语法错误:'('意外。
syntax error at line 10: 'then' unexpected. 第10行的语法错误:'然后'意外。
syntax error at line 13: 'fi' unexpected etc. 第13行的语法错误:'fi'意外等
What is the problem with this script? 这个脚本有什么问题?
bash version - GNU bash, version 3.00.16(1)-release (sparc-sun-solaris2.10) bash版本 - GNU bash,版本3.00.16(1)-release(sparc-sun-solaris2.10)
The basic problem with the script is spacing. 脚本的基本问题是间距。 You have spaces where you shouldn't have them:
你有空间,你不应该有它们:
(wrong) count = $((count+1))
(right) count=$((count+1))
(better) ((count++))
and you're missing spaces where you need them: 你错过了你需要它们的空间:
(wrong) if[ $count%100 -eq 0 ]
(right) if [ $((count % 100)) -eq 0 ]
(better) if ((count % 100 == 0))
count = $((count+1))
tries to run the command count
passing it two arguments, =
and the value of count+1
. count = $((count+1))
尝试运行命令count
传递两个参数, =
和count+1
的值。 if[ ...
tries to run the command if[
because [
is a valid word character; if[ ...
试图运行命令, if[
因为[
是一个有效的单词字符; it doesn't automatically start a new token. 它不会自动启动新令牌。
Having said all that, I'm puzzled by the unexpected (
error message. Could your bash be too old to recognize $((
syntax? Possibly. It's a very old bash. 说完这一切之后,我对这个
unexpected (
事情感到困惑unexpected (
错误消息。你的bash可能太老而无法识别$((
语法?可能。这是一个非常古老的bash。
count=$((count+1))
if [ `echo $count % 100 | bc` -eq 0 ]
Make these corrections. 进行这些更正。
Edit: Please try 编辑:请尝试
count=`expr $count + 1`
I see a few errors here. 我在这里看到一些错误。 First, you need double quotes around
$i
in case they have special characters. 首先,如果它们有特殊字符,你需要在
$i
附近$i
双引号。
Second, you shouldn't ever use 其次,你不应该使用
for i in `ls | sort -n`
Instead, try the following 相反,请尝试以下方法
ls -1 | sort -n | while read i
Third, change your if statement to 第三,将你的if语句改为
if ((count%5 == 0))
The ((
syntax is bash is made just for integer math. ((
语法是bash只用于整数数学。
Fourth, change your counter increment to 第四,将你的计数器增量改为
((count++))
This is more concise. 这更简洁。 Also, the space in your version may break things.
此外,您的版本中的空间可能会破坏事物。 Remember, spaces matter.
请记住,空间很重要。
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