如何在python中X秒后引发超时异常

Question

I have a function and I need to raise exception after X seconds how can I do this? I try this code but It doesen't work:

from eventlet.timeout import Timeout
timeout = Timeout(seconds, exception)
try:
   do somethins
finally:
   timeout.cancel()

Answer 1

According to the timeout documentation :

There are two Timeout caveats to be aware of:

• If the code block in the try/finally or with-block never cooperatively yields, the timeout cannot be raised. In Eventlet, this should rarely be a problem, but be aware that you cannot time out CPU-only operations with this class.
• If the code block catches and doesn't re-raise BaseException (for example, with except:), then it will catch the Timeout exception, and might not abort as intended.

If you are doing expensive calculation without doing any IO/ sleep in a loop, timeout will not occur.