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NodeJS + MongoDB ASYNC结果出现较晚

[英]NodeJS + MongoDB ASYNC results appearing late

I have a simple function which returns a list of connected users in a channel, I was using it in a initial stage with a simple array, but know, I want to retrieve some user details from the mongodb database and add it to that array. 我有一个简单的函数,它返回通道中已连接用户的列表,我在初始阶段就使用了一个简单的数组,但是知道,我想从mongodb数据库中检索一些用户详细信息并将其添加到该数组中。

The problem that I'm having is that the return is giving an empty result, I can clearly see later on in the console log that is because the queries are running late and the return is running before having the results back. 我遇到的问题是,返回的结果为空,我稍后可以在控制台日志中清楚地看到这是因为查询运行较晚,并且返回的结果是返回之前的结果。

I know it is because the asynchronous functions, I've tried with Q and others but I just simply cant get it working. 我知道这是因为异步函数,我已经尝试过Q和其他函数,但是我只是无法使其正常工作。 :( :(

//GET USERS FOR SPECIFIED ROOM
function get_room_users( room ){

    // create an array to hold all the usernames of the poeple in a specific room
    var roomusers = new Array();        

    // get all the clients in ‘room1′
    var clients = io.sockets.clients( room );

    var i = 0;

    for(var i = 0; i < clients.length; i++) {

        db.users.findOne( { email: clients[i].username }, function(err, userdata) {

            if( err || ! userdata ){

                console.log('no user found');

            } else { 
                console.log("DISPLAYING USER DATA: " + userdata.nickname);
                roomusers[roomusers.length] = userdata.nickname;


                console.log("HERE THE CONSOLE SHOWS ROOMUSERS FILLED IN");
                console.log(roomusers);

                i++;

            }

        });

    }

    console.log("HERE THE ARRAY LOOKS EMPTY BEFORE SENDING BACK");
    console.log(roomusers);

    return roomusers;


}

var users = get_room_users(room1);

console.log("HERE THE ARRAY LOOKS EMPTY!")
console.log(users);

CONSOLE LOG RESULT 控制台日志结果

HERE THE ARRAY LOOKS EMPTY BEFORE SENDING BACK
[]
HERE THE ARRAY LOOKS EMPTY!
[]
HERE THE CONSOLE SHOWS ROOMUSERS FILLED IN
['user@user.com']

FINALLY RESOLVED: Ok, so as one of the users commented I was thinking in a synchronous mode, I changed the emit method up after the bucle got resolved in order to emit when everything has been done. 最终解决:好的,正如其中一位用户评论的那样,我正在考虑以同步模式进行操作,在解决了气泡之后,我更改了send方法,以便在完成所有操作后进行发射。 Keep in mind that I'm using Q to create promisses :) 请记住,我正在使用Q创建委托:)

//GET USERS FOR SPECIFIED ROOM function get_room_users( room ){ //获取指定房间的用户功能get_room_users(room){

var the_promises = [];

// create an array to hold all the usernames of the poeple in a specific room
var roomusers = new Array();        

// get all the clients in ‘room1′
var clients = io.sockets.clients( room );

clients.forEach(function (socket) {

    var deferred = Q.defer();

    db.usuarios.findOne( { email: socket.username }, function(err, userdata) {

        if( err || ! userdata ){

            console.log('no user found');
            deferred.reject();

        } else { 
            console.log("DISPLAYING USER DATA: " + socket.username);
            roomusers[roomusers.length] = socket.username;

            console.log("DENTRO DEL BUCLE");
            console.log(roomusers);

            deferred.resolve();

        }

    });

    the_promises.push(deferred.promise);    


});


Q.all(the_promises).done( function(){   
    console.log("ALL THINGS DONE!"); 
    // broadcast to everyone in room 1 the usernames of the clients connected.
    io.sockets.to( room ).emit('updateroomusers', roomusers);   
 } );

} }

I suggest you to use Q Promises ( https://npmjs.org/package/q ). 我建议您使用Q Promises( https://npmjs.org/package/q )。 Promises is a very powerfull tool for scheduling asynchronous operations. Promises是用于调度异步操作的非常强大的工具。

Yes, this is a problem of using a synchronous style on an asynchronous environment. 是的,这是在异步环境中使用同步样式的问题。 Execution runs ahead of io.sockets.clients( room ) before a response comes back. 在响应返回之前,执行先于io.sockets.clients( room )运行。

The following should work: 以下应该工作:

io.sockets.clients(room).forEach(function (socket) {
    // Your for-loop code
    db.users.findOne( ... );
});

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