[英]capset fails with pointer to struct
I have two code samples: 我有两个代码示例:
First, runs correctly: 首先,正确运行:
#include <sys/capability.h>
#include <unistd.h>
#include <cstdio>
int main()
{
__user_cap_header_struct *hdr = new __user_cap_header_struct;
__user_cap_data_struct *data = new __user_cap_data_struct;
hdr->pid = getpid();
hdr->version = _LINUX_CAPABILITY_VERSION;
data->effective &= ~CAP_TO_MASK(CAP_IPC_LOCK);
data->permitted &= ~CAP_TO_MASK(CAP_IPC_LOCK);
data->inheritable = 0;
if (capset(hdr, data) < 0)
printf("capset failed: %m");
return 0
}
Second, fail: Operation not permitted
: 二,
fail: Operation not permitted
:
#include <sys/capability.h>
#include <unistd.h>
#include <cstdio>
int main()
{
struct __user_cap_header_struct hdr;
hdr.pid = getpid();
hdr.version = _LINUX_CAPABILITY_VERSION;
struct __user_cap_data_struct data;
data.effective &= ~CAP_TO_MASK(CAP_IPC_LOCK);
data.permitted &= ~CAP_TO_MASK(CAP_IPC_LOCK);
if(capset(&hdr, &data))
printf("capset failed: %m");
return 0;
}
I think both code samples are the same. 我认为两个代码示例是相同的。
When I run the first one it executes correctly (uses pointer to struct). 当我运行第一个时,它可以正确执行(使用指向struct的指针)。
But the second fails (uses instance of struct). 但是第二个失败(使用struct实例)。
I don't know why. 我不知道为什么 Can you help me?
你能帮助我吗?
Most likely because how the structures are initialized. 最有可能是因为如何初始化结构。 When declaring a local variable, its value is indeterminate , using that value then leads to undefined behavior .
声明局部变量时,其值是不确定的 ,使用该值会导致未定义的行为 。
The same goes for local structure variables. 局部结构变量也是如此。 The member field values are simply undefined, so when you do eg
data.effective &= ~CAP_TO_MASK(CAP_IPC_LOCK);
成员字段的值只是未定义的,所以当您执行例如
data.effective &= ~CAP_TO_MASK(CAP_IPC_LOCK);
you use an indeterminate (and seemingly random) value for the operation. 您对操作使用不确定的(看似随机的)值。
You need to initialize the structure to a well know value before using it. 您需要在使用结构之前将其初始化为众所周知的值。 Like
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struct __user_cap_header_struct hdr = { 0 };
The above will set all fields in the structure to zero. 上面的代码将结构中的所有字段设置为零。
When you allocate with new
(which is C++ and not C!) then for structures (or classes) without default constructors all member fields are default constructed , and for integer fields this means they are zeroed. 当使用
new
(是C ++而不是C!)进行分配时,对于没有默认构造函数的结构(或类),所有成员字段都是默认构造的 ,对于整数字段,这意味着它们将被清零。 If you allocated the structures in the first example using malloc
(as that's the C way of allocating memory) then you would have the same result as the second example, as then the allocated memory would not be initialized at all. 如果您在第一个示例中使用
malloc
分配了结构(因为这是分配内存的C方法),那么您将获得与第二个示例相同的结果,因为分配的内存根本不会初始化。
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