[英]creating list of empty lists - Python
test = [[None for e in range(1)] for e in range(len(foobar)/2)]
for delete in range(0,len(test)):
del test[delete][0]
This is not the most pythonic way to create an empty list
这不是创建empty list
的最pythonic方法
would you suggest something else? 你还能提出其他建议吗?
I know that this question explains it. 我知道这个问题可以解释。 but this is not a duplicate of the previous one as you can see. 但这不是您看到的上一个的重复。
Does this do what you want? 这是您想要的吗?
test = [[] for e in range(len(foobar)/2)]
It has the same output as your code 它的输出与您的代码相同
test = [[None for e in range(1)] for e in range(len(foobar)/2)]
can be simplified to: 可以简化为:
test = [[] for i in xrange(len(foobar)/2)]
Also don't forget to use xrange
instead of range
, as it returns a generator and not a complete list 同样不要忘记使用xrange
而不是range
,因为它会返回生成器而不是完整列表
An empty list: 空列表:
test = []
Unless we're missing something ;-) 除非我们缺少什么;-)
Or you want an list of empty lists of a given length? 还是想要一个给定长度的空列表?
n = 100
test = [ [] for i in range(0,n) ]
test = map(lambda x: [], foobar[:len(foobar)/2])
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