如何在java中的特定字符后修剪字符串

Question

I have a string variable in java having value:

String result="34.1 -118.33\n<!--ABCDEFG-->";

I want my final string to contain the value:

String result="34.1 -118.33";

How can I do this? I'm new to java programming language.

Thanks,

Answer 1

您可以使用：

result = result.split("\n")[0];

Answer 2

Assuming you just want everything before \\n (or any other literal string/char), you should use indexOf() with substring() :

result = result.substring(0, result.indexOf('\n'));

If you want to extract the portion before a certain regular expression, you can use split() :

result = result.split(regex, 2)[0];

---

String result = "34.1 -118.33\n<!--ABCDEFG-->";

System.out.println(result.substring(0, result.indexOf('\n')));
System.out.println(result.split("\n", 2)[0]);

34.1 -118.33
34.1 -118.33

(Obviously \\n isn't a meaningful regular expression, I just used it to demonstrate that the second approach also works.)

Answer 3

There are many good answers, but I would use StringUtils from commons-lang . I find StringUtils.substringBefore() more readable than the alternatives:

String result = StringUtils.substringBefore("34.1 -118.33\n<!--ABCDEFG-->", "\n");

Answer 4

Use regex:

result = result.replaceAll("\n.*", "");

replaceAll() uses regex to find its target, which I have replaced with "nothing" - effectively deleting the target.

The target I've specified by the regex \\n.* means "the newline char and everything after"

Answer 5

How about

Scanner scanner = new Scanner(result);
String line = scanner.nextLine();//will contain 34.1 -118.33

Answer 6

You could use result = result.replaceAll("\\n",""); or

 String[] split = result.split("\n");

Answer 7

Try this:

String result = "34.1 -118.33\n<!--ABCDEFG-->";
result = result.substring(0, result.indexOf("\n"));

Answer 8

使用Scanner并传入分隔符和原始字符串：

result = new Scanner(result).useDelimiter("\n").next();

Answer 9

you can use StringTokenizer :

StringTokenizer st = new StringTokenizer("34.1 -118.33\n<!--ABCDEFG-->", "\n");
System.out.println(st.nextToken());

output :

34.1 -118.33

Answer 10

This is the simplest method you can do and reduce your efforts. just paste this function in your class and call it anywhere:

you can do this by creating a substring.

simple exampe is here:

 public static String removeTillWord(String input, String word) { return input.substring(input.indexOf(word)); } removeTillWord("Your String", "\\");