[英]Comparing two values set in MySQL table php
I have a mysql table that has 2 columns, claim_status and show (both VARCHAR(500)) I tested with int didn't work. 我有一个具有2列的mysql表,claim_status和show(都是VARCHAR(500)),我用int测试过后不起作用。
I want to query only the items that have claim_status='0' and show='1' 我只想查询具有Claim_status ='0'和show ='1'的项目
right now nothing is returned here is my PHP code: 现在什么都没有返回,这是我的PHP代码:
$query = "SELECT COUNT(*) as num FROM $tableName WHERE claim_status='0' AND show='1'";
$query1 = "SELECT * FROM $tableName WHERE claim_status='0' AND show='1'";
** it fails on this line ** $query = "SELECT COUNT(*) as num FROM $tableName WHERE claim_status=0 AND show=1"; **它在此行上失败** $ query =“ SELECT COUNT(*)as num FROM $ tableName WHERE Claim_status = 0 AND show = 1”;
$query = SELECT * FROM tablename WHERE claim_status='0' AND show='1';
$result = mysql_query($query);
if (!$result) {
die('Invalid query: ' . mysql_error());
}
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