[英]simple mysql function syntax error 1064
I cant figure outt the error in this function that i wrote. 我想不出我写的这个函数中的错误。 I suspect that it must be something with type casting. 我怀疑这一定是类型转换。 i tried to comment part by part to see where the error may be and it was somewhere after the first IF and before return. 我试图逐条注释,以查看错误可能在哪里,它在第一个IF之后到返回之前的某个地方。 I would really appreciate if someone could help me figure it out. 如果有人可以帮助我解决问题,我将不胜感激。 the error is 1064 and it says that syntax is missing near ' ' line 33. 错误为1064,表示在''第33行附近缺少语法。
DELIMITER $$
CREATE DEFINER=`root`@`localhost` FUNCTION `substation1`(`subofficecode` INT,`productcat` VARCHAR(5),`ALN` INT(1)) RETURNS VARCHAR(10)
READS SQL DATA
BEGIN
DECLARE substation_ID VARCHAR(10);
DECLARE pcat VARCHAR(2);
DECLARE i INT;
IF (LENGTH (subofficecode) < 3) THEN
SET substation_ID= CONCAT ('0',subofficecode);
ELSE IF (LENGTH (subofficecode) < 2) THEN
SET substation_ID= CONCAT ('00',subofficecode);
ELSE
SET substation_ID= CONCAT('',subofficecode);
END IF;
IF (STRCMP(productcat,'REF')=0) THEN
SET pcat = '11';
ELSE IF (STRCMP(productcat,'DF')=0) THEN
SET pcat='12';
ELSE IF (STRCMP(productcat,'MWO')=0) THEN
SET pcat='13';
ELSE IF (STRCMP(productcat,'WM')=0) THEN
SET pcat='14';
ELSE IF (STRCMP(productcat,'SPLIT')=0) THEN
SET pcat='15';
ELSE
SET pcat='16';
END IF;
SET i=(SELECT MAX(substationid) FROM substation) + 1;
SET substation_ID=CONCAT(substation_ID,pcat,ALN,i);
RETURN substation_ID;
END$$
DELIMITER ;
At the bare minimum, when chaining conditions in an IF
statement, the right syntax is ELSEIF
not ELSE IF
. 至少,当在IF
语句中链接条件时,正确的语法是ELSEIF
而不是ELSE IF
。
IF search_condition THEN statement_list [ELSEIF search_condition THEN statement_list] ... [ELSE statement_list] END IF
See http://dev.mysql.com/doc/refman/5.0/en/if.html for the supported syntax 有关支持的语法,请参见http://dev.mysql.com/doc/refman/5.0/en/if.html
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