[英]Get element by tag name and class name
(in vanilla JavaScript) I was wondering if the was an easy way to do something like (在vanilla JavaScript中)我想知道这是否是一种简单的方法
x = document.getElementsByTagName('span') && getElementsByClassName('null');
To return all 'span' elements that have the class name 'null'? 要返回类名为“null”的所有“span”元素?
I thought it might have been something like: 我以为它可能是这样的:
x = document.getElementsByTagName('span');
x = x.getElementsByClassName('null');
// or
x = document.getElementsByTagName('span').getElementsByClassName('null');
But that didn't seem to work out. 但这似乎没有成功。
Is this possible or will I have to iterate through x popping anything that returns false for .class='null'? 这是可能的还是我必须迭代x弹出任何返回false的.class ='null'?
Thanks. 谢谢。
The DOM does not provide any APIs for filtering NodeLists. DOM不提供任何用于过滤NodeLists的API。
Instead, you can use CSS selectors: 相反,您可以使用CSS选择器:
var x = document.querySelectorAll('span.null');
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