[英]Error handling with inputdlg
Below is an input dialog box I'm using in a program. 下面是我在程序中使用的输入对话框。 Does anyone know how to "nicely" handle the case when the user input is not a number?
没有人知道当用户输入的数字不是数字时如何“巧妙地”处理这种情况吗? Also, if the number is outside the range minlev - maxlev then the error dialog pops up, but you cannot press the OK button because the input dialog pops up in front of it.
另外,如果数字在minlev-maxlev范围之外,则会弹出错误对话框,但是您不能按OK按钮,因为输入对话框会弹出在其前面。 Does anyone know how to fix this?
有谁知道如何解决这一问题?
RVP= 1;
while ( RVP )
prompt = {'Enter the corridor width (1050-1400mm) :'};
dlg_title = 'Input';
num_lines=1;
answer = inputdlg(prompt,dlg_title,num_lines);
if(str2num(answer{1})<1050 || (str2num(answer{1})>1400))
errordlg('Number is out of range');
else
w1 = (2*answer{1}-1050-1400)/(1400-1050)
end
end
Use isnumeric
. 使用
isnumeric
。 Then you can re-call the inputdlg after the error dialog. 然后,您可以在错误对话框之后重新调用inputdlg。
To keep the errordlg box from being covered up, use uiwait. 为了防止errordlg框被遮盖,请使用uiwait。
while ( RVP )
prompt = {'Enter the corridor width (1050-1400mm) :'};
dlg_title = 'Input';
num_lines=1;
answer = inputdlg(prompt,dlg_title,num_lines);
if ~isnumeric(answer) || (str2num(answer{1})<1050 || (str2num(answer{1})>1400))
uiwait(errordlg('Number is out of range'));
answer = inputdlg({'Please enter a valid input (1050-1400mm) :'},...
dlg_title,num_lines);
end
w1 = (2*answer{1}-1050-1400)/(1400-1050)
end
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