如何在 CURL shell 脚本中捕获超时/错误？

Question

I want to issue a cURL GET request to a URL and based on the return HTTP code decide whether to do something with the returned HTTP data.

For example, if the HTTP code for a certain url request through cURL is valid (not timed out or error), then keep the returned data from the request somewhere in my system.

How can I actually 'catch' the returned HTTP code (or timeout) and do the decision based on that?

Answer 1

Execute following as script.sh http://www.google.com/ .
-D - dump headers to file
-o - write response to file
-s - be silent
-w - display value of specified variables

#!/bin/bash

RESPONSE=response.txt
HEADERS=headers.txt

status=$(curl -s -w %{http_code} $1 -o $RESPONSE)

# or
#curl -s -D $HEADERS $1 -o $RESPONSE
#status=$(cat $HEADERS | head -n 1 | awk '{print $2}')

echo $status

Use $status and $RESPONSE for further processing.

Answer 2

if you're trying to store the http response to a variable.

#!bin/bash

STATUS_RECEIVED=$(curl -s --write-out "%{http_code}\n" $envUrl --output output.txt --silent) ;

echo $STATUS_RECEIVED