如何从字符串的开头和结尾删除符号，除了某些符号？

Question

I am currently using this regex:

/^[^a-z\d]*|[^a-z\d]*$/gi

This checks for a symbol in the beginning and end of a string.

However, I want to exclude these 4 symbols from being removed:

(
)
[
]

How can I modify my regex so that it doesn't remove those symbols?

Answer 1

Then you can add them to the excludes list:

/^[^\(\[\)\]a-z\d]*|[^\(\[\)\]a-z\d]*$/gi

(if I understand correctly and you want to remove all symbols up to the first occurence of one of these symbols - if not, this will not be a single regex, I think)

Answer 2

Here is Fiddle

It can remove all the special characters include ()[]

var test = "([xxxx † yyyy § zzzz)]";
alert(test.replace(/[`~!@#$%^&*()_|+\-=?;:'",.<>\{\}\[\]\\\/]/gi, ''));