sed 同时删除单引号和双引号

Question

I am trying to remove single quotes and double quotes from a file. Can I do it in a single sed command?

I am trying :

sed 's/\"//g;s/\'//g' txt file

but get this error

`' ' is unmatched.

Please help.

Answer 1

另一种可能性是使用tr ：

tr -d \'\" file

Answer 2

You cannot escape a single quote inside a pair of singe quotes in shell. Escaping double quotes is allowed though. Following sed command should work:

sed "s/['\"]//g" file

Answer 3

试试这个：

sed -e 's|["'\'']||g' txt

Answer 4

要删除单引号，只需对sed的正则表达式使用双引号：

sed -e "s/'//g" ./new_file.csv

Answer 5

You can use commands below

sed "s/'/ /g" file.txt > newfile.txt
sed 's/\"//g' newfile.txt > Required_file.txt

Required_file.txt is the final output.

Answer 6

我通过删除周围的引号来解决它（在Centos 7 ），例如：

sed -i s/\'//g file;sed -i s/\"//g file 

Answer 7

Well, here's what I've came to.

First, I found out with ord() what are codes for single and double quotes characters, and then used $(..) syntax to pass it into unquoted sed expression. I used XX and yy instead of empty strings. Obviously it is faaar from optimal, ie they perhaps should be combined into one expression, I encourage you to experiment with it. There are several techniques to avoid quoting problems, you can also put sed expression into separate file, to avoid it to be interpreted by shell. The ord() / chr() trick is also useful when trying to deal with single unreadable characters in output, eg UTF strings on non-UTF console.

dtpwmbp:~ pwadas$ echo '"' | perl -pe 'print ord($_) . "\n";'
34
"
dtpwmbp:~ pwadas$ echo "'" | perl -pe 'print ord($_) . "\n";'
39
'
dtpwmbp:~ pwadas$ echo \'\" 
'"
dtpwmbp:~ pwadas$ echo \'\" | sed -e s/$(perl -e 'print chr(34) . "\n"')/XX/g | sed -e s/$(perl -e 'print chr(39) . "\n"')/yy/g 
yyXX
dtpwmbp:~ pwadas$

EDIT (note that this time, both characters are replaced with the same string "yy").There might be some shell utilities for "translating" characters to character codes and opposite, ie it should be possible to do this without using perl or other language interpreter.

dtpwmbp:~ pwadas$ echo \'\" | sed -e s/[`perl -e 'print chr(34) . chr(39)'`]/yy/g
yyyy
dtpwmbp:~ pwadas$ 

and here's yet another way in shell, perhaps even simpler

dtpwmbp:~ pwadas$ X="'"; Y='"' ; echo $X$Y; echo $X$Y | sed -e "s/$X/aa/g;s/$Y/bb/g"
'"
aabb
dtpwmbp:~ pwadas$