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如何通过类名获取类类型?

[英]How to get class type by its class name?

namespace Myspace
{
    public class MyClass
    {
    }
} //This class is in another file.

using Myspace;
static void Main(string[] args)
{
    Regex regexViewModelKey = new Regex(RegularExpr.ViewModelKeyPattern);
    string viewModel = regexViewModelKey.Match(match.Value).Value;
    //Now, vieModel is a string, and its value is "MyClass". So, I only know the class name, this is why I ask this question.

    //Now, I'm only allowed to use the string form of this class name to get its type.
    //I have tyied like this, but its no use.
    Type t = Type.GetType(viewModel);
    //it's return a null.

    //Then I tyied another method like this, but there is an exception when calling Assembly.Load
    Assembly assembly = Assembly.Load("Myspace");
    Type ty = assembly.GetType("Myspace" + viewModel);
}

I hope my question is clear.我希望我的问题很清楚。 Can any one help me.THX I'm only allowed to use the string form of this class name to get its type.任何人都可以帮助我。THX 我只允许使用此类名称的字符串形式来获取其类型。

thx everyone.谢谢大家。 I have solved this question by myself like this.我已经像这样自己解决了这个问题。

{
      Type t = Type.GetType(string.Concat(viewModel, ",", "Myspace"));
}

just use the function typeof().只需使用函数 typeof()。 The parameter is just that class name.参数就是那个类名。

Type type = typeof(FIXProtoClientTest);

MSDN on typeof() MSDN 关于 typeof()

Generally speaking, you'll hardly ever need to do type comparisons unless you're doing something with reflection or interfaces.一般来说,除非您使用反射或接口做一些事情,否则您几乎不需要进行类型比较。 Nonetheless:尽管如此:

If you know the type you want to compare it with, use the is or as operators:如果您知道要与之比较的类型,请使用isas运算符:

if( unknownObject is TypeIKnow ) { // run code here

The as operator performs a cast that returns null if it fails rather than an exception: as运算符执行强制转换,如果失败而不是异常则返回null

TypeIKnow typed = unknownObject as TypeIKnow;

If you don't know the type and just want runtime type information, use the .GetType() method:如果您不知道类型而只想要运行时类型信息,请使用.GetType()方法:

Type typeInformation = unknownObject.GetType();



     // int is a value type
    int i = 0;
    // Prints True for any value of i
    Console.WriteLine(i.GetType() == typeof(int));

    // string is a sealed reference type
    string s = "Foo";
    // Prints True for any value of s
    Console.WriteLine(s == null || s.GetType() == typeof(string));

    // object is an unsealed reference type
    object o = new FileInfo("C:\\f.txt");
    // Prints False, but could be true for some values of o
    Console.WriteLine(o == null || o.GetType() == typeof(object));

 // Get the type of a specified class.
                Type myType1 = Type.GetType("System.Int32");
                Console.WriteLine("The full name is {0}.", myType1.FullName);
                // Since NoneSuch does not exist in this assembly, GetType throws a TypeLoadException.
                Type myType2 = Type.GetType("NoneSuch", true);
                Console.WriteLine("The full name is {0}.", myType2.FullName);

    // FileSystemInfo is an abstract type
    FileSystemInfo fsi = new DirectoryInfo("C:\\");
    // Prints False for all non-null values of fsi
    Console.WriteLine(fsi == null || fsi.GetType() == typeof(FileSystemInfo));

Your line Type.GetType(model) will work if you use the fully qualified class name, including its namespace.如果您使用完全限定的类名,包括其命名空间,您的行 Type.GetType(model) 将起作用。

Furthermore, if it's in a different assembly from the code that makes the call you should use Assembly.GetType(typeName) when the assembly object referred to is an instance of the assembly containing the type.此外,如果它与进行调用的代码位于不同的程序集中,则当引用的程序集对象是包含该类型的程序集的实例时,您应该使用 Assembly.GetType(typeName)。

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