[英]How to split a string in chunks of eight chars?
I have following binary string 我有以下二进制字符串
string binaryString = "110011100110011011001110011001101100111001100110110011100110011011001110001001100110011011001110";
Now I want to split the above string into group of 8 characters. 现在我想将上面的字符串拆分为8个字符的组。 eg.
例如。
11001110 11001110 11001110 11001110 11001110 11001110
I tried following code but not getting expected result 我尝试了下面的代码但没有得到预期的结果
var binary = binaryString.Where((x, y) => y % 8 == 0).ToList();
Try this: 尝试这个:
IEnumerable<string> groups = Enumerable.Range(0, binaryString.Length / 8)
.Select(i => binaryString.Substring(i * 8, 8));
How about like? 怎么样?
string binaryString = "110011100110011011001110011001101100111001100110110011100110011011001110001001100110011011001110";
int step = binaryString.Length / 8;
for (int i = 0; i < step; i++)
{
Console.WriteLine(binaryString.Substring(i, 8));
}
Output will be; 输出将是;
11001110
10011100
00111001
01110011
11100110
11001100
10011001
00110011
01100110
11001101
10011011
00110110
List<string> bytes = binaryString.Select((c, i) => new { c, i })
.GroupBy(x => x.i / 8)
.Select(x => String.Join("",x.Select(y => y.c)))
.ToList();
In pure LINQ it's something like this: 在纯LINQ中,它是这样的:
var parts = Enumerable.Range(0, (binaryString.Length + 7) / 8)
.Select(p => binaryString.Substring(p * 8, Math.Min(8, binaryString.Length - (p * 8))))
.ToArray();
It's quite complex because it's able to "parse" ranges smaller than 8 characters. 它非常复杂,因为它能够“解析”小于8个字符的范围。 So:
所以:
string binaryString = "123456781234567"
will return 12345678, 1234567 将返回12345678,1234567
(binaryString.Length + 7) / 8)
This is the number of parts we will have. 这是我们将拥有的零件数量。 We have to round up clearly, so "0" is a part, and "123456781" are two parts.
我们必须清楚地整理,所以“0”是一部分,“123456781”是两部分。 By adding (divisor - 1) we are rounding up.
通过添加(除数-1),我们正在四舍五入。
Enumerable.Range(0, (binaryString.Length + 7) / 8)
This will give a sequence of numbers 0, 1, 2, # of parts - 1 这将给出一系列数字0,1,2,#of parts - 1
.Select(p =>
The select :-) 选择:-)
binaryString.Substring(p * 8, Math.Min(8, binaryString.Length - (p * 8))))
The Substring 子串
p * 8
The starting point, the part number * 8, (so part #0 starts at 0, part #1 starts at 8...) 起点,零件号* 8,(因此零件#0从0开始,零件#1从8开始......)
Math.Min(8, binaryString.Length - (p * 8)))
Normally it would be 8, but the last part could be shorter. 通常它会是8,但最后一部分可能会更短。 It means the
Min
between 8
and the number of remaining characters. 它表示
Min
在8
和剩余字符数之间。
With a Regex it's perhaps easier: 使用正则表达式可能更容易:
var parts2 = Regex.Matches(binaryString, ".{1,8}")
.OfType<Match>()
.Select(p => p.ToString())
.ToArray();
(captures groups of 1-8 characters, any character, then take the matches and put them in an array) (捕获1-8个字符的组,任何字符,然后获取匹配并将它们放入数组中)
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