是否有更惯用的方法来获取Clojure中的N个随机元素？

Question

I'm currrently doing this: (repeatedly n #(rand-nth (seq coll))) but I suspect there might be a more idiomatic way, for 2 reasons:

• I've found that there's frequently a more concise and expressive alternative to using short anonymous functions, eg partial
• the docstring for repeatedly says “presumably with side effects”, implying that it's not intended to be used to produce values

I suppose I could figure out a way to use reduce but that seems like it would be tricky and less efficient, as it would have to process the entire collection, since reduce is not lazy.

Answer 1

An easy solution but not optimal for big collections could be:

(take n (shuffle coll))

Has the "advantage" of not repeating elements. Also you could implement a lazy-shuffle but it will involve more code.

Answer 2

I know it's not exactly what you're asking - but if you're doing a lot of sampling and statistical work, you might be interested in Incanter ( [incanter "1.5.2"] ). Incanter provides the function sample , which provides options for sample size, and replacement.

(require '[incanter.stats :refer [sample]]))

(sample [1 2 3 4 5 6 7] :size 5 :replacement false) 
; => (1 5 6 2 7)