PHP如何过滤数组值

Question

I'm trying to show in a div 3 thumbnails stored in different folders.
In my bd determined (with value "1") which record has pictures. So this is my db:

+------+----------------+---------+--------+--------+
| ID   | BRAND          |   PHP   |  RUBY  |  JAVA  |
+------+----------------+---------+--------+--------+
| 1    | ford           |    1    |    0   |    0   |
+------+----------------+---------+--------+--------+
| 2    | seat           |    1    |    1   |    1   |
+------+----------------+---------+--------+--------+
| 3    | fiat           |    1    |    1   |    0   |
+------+----------------+---------+--------+--------+
| 4    | toyota         |    1    |    0   |    0   |
+------+----------------+---------+--------+--------+
| 5    | vw             |    1    |    0   |    1   |
+------+----------------+---------+--------+--------+

Selecting records:

$result = mysqli_query($connecDB,"SELECT * FROM brands WHERE php = '1' OR ruby = '1' OR java = '1' ORDER BY id ASC");


while($row = mysqli_fetch_assoc($result)){
    $new_array[] = $row;
}

But my problem is: How I can select the values ​​"1" and how to know which is which?
Maybe I could use: $row['php'] $row['java'] $row['ruby'] But how to filter the values ​​"0"?

Answer 1

It looks like you want to break up the array into php, java, and ruby. Below is not tested, just to give you an idea.

$resultsArray = array();
while($row = mysqli_fetch_assoc($result)){
    if($row['php'] == 1) {
        $resultsArray['php'][] = $row['id'];
    }
    if($row['java'] == 1) {
        $resultsArray['java'][] = $row['id'];
    }
    if($row['ruby'] == 1) {
        $resultsArray['ruby'][] = $row['id'];
    }
}

Then loop through that 2d array, grabbing the name from the key in resultsArray.

foreach($resultsArray as $language => $array) {
    foreach($array as $id) {
        echo "url/".$language."/".$id;
        echo "<br>";
    }
}

Answer 2

foreach($resultsArray as $language => $array){
    foreach(array_slice(glob('work/'.$language.'/'.$rowtest['id'].'/*.jpg'),0,1) as $image){    
        echo $image . "<br />";
    }
}