从此日期获取行到此日期

Question

i really couldn't get it.

code-

select * 
from Bill_Detail 
where DateTimeofBilling > '8/18/2013 12:00:00 PM' 
  and DateTimeofBilling < '8/20/2013 12:00:00 AM'

psudocode-

select all 
from Bill_Detail 
where DateTimeofBilling greater than 8/18/2013 
  and DateTimeofBilling less than 8/20/2013

i need to get the rows from the date 8/18/2013 to 8/20/2013 but the code returns nothing.

i think this is enough explanation for this . can anyone help?

Answer 1

Why do you use PM (noon, not midnight) for the "greater than" check? Your pseudocode assumes that you also want to use PM.

select * 
from Bill_Detail 
where DateTimeofBilling >= '20130818'-- if you want to include this day completely
  and DateTimeofBilling < '20130820' -- if you want to exclude this day completely

Answer 2

尝试这个..

select * from Bill_Detail where DateTimeofBilling > '2013/08/18 12:00:00 PM' and DateTimeofBilling < '2013/08/20 12:00:00 AM'

Answer 3

If your column DateTimeofBilling is type datetime, compare it with date and not with varchar:

select * 
from Bill_Detail 
where
    DateTimeofBilling >= convert(date, '20130818', 112) and
    DateTimeofBilling < convert(date, '20130821', 112)

this one will return you rows with DateTimeofBilling where date is more or equal 2013-08-18 and less or equal 2013-08-20

Answer 4

Using between

SELECT *
FROM Bill_Detail
WHERE DateTimeofBilling BETWEEN '20130818 000000' 
    AND DateTimeofBilling < '2013/08/20 12:00:00 AM'

Answer 5

尝试这个，

select * from Bill_Detail where DateTimeofBilling between '8/18/2013 12:00:00 PM' and  '8/20/2013 12:00:00 AM'

Answer 6

SELECT * FROM Bill_Detail WHERE DateTimeofBilling>='8/18/2013 12:00:00 PM' AND DateTimeofBilling<='8/20/2013 12:00:00 AM' ORDER BY DateTimeofBilling