打印出C ++中的循环链表？

Question

I want to print out a circular linked list. How would you print them out?

This one is for regular linked list. And if I implement this for circular list, it loops for ever. Any idea to restrict and print out just one circle?

struct node* curr_node_1 = head;
while ( curr_node_1 != nullptr )
{
    cout << curr_node_1->p_data << ", ";
    curr_node_1 = curr_node_1->p_next;
}

And my node struct is following

 struct node
 {
    int            p_data;
    struct node*   p_next;

    node(node* head, int data)
    {
        p_next = head;
        p_data = data;
    }

    explicit node(int data)
    {
        p_next = nullptr;
        p_data = data;
    }
 };

Answer 1

Just replace the column ending condition with head instead of nullptr and take care that the loop is run through at all:

struct node* curr_node_1 = head;
if(curr_node_1 != nullptr)
{
    do
    {
        cout << curr_node_1->p_data << ", ";
        curr_node_1 = curr_node_1->p_next;
    } while ( curr_node_1 != head );
}