打开另一个弹出窗口时关闭一个弹出窗口

Question

I have icons in my rich text area - icons for: link, insert image, insert column. On each button when clicked it opens a popup which the user completes the task. Each button functions like this went clicked:

onclick="$.Forms.WysiHtml5.InitEditor($(this));"

and when the click on the icon again it disappears:

onclick="$.Forms.WysiHtml5.ClosePopover($(this));"

Problem:
When i click a button and popup shows then i go click another button - another popup comes up leaving the page with two popups showing. I want it so that when i click on a button if there is a popup it will close and new popup for the clicked button will show.

Based on suggested answer below:

'<a class="btn popover_btn" href="javascript:;" title="' + locale.css.columns.insert + '"'
                                    + 'data-placement="top" data-popover-selector="#RichText_ColsPopover"'
                                    + '$(#DynamicEditorForm)on("click", ".tool", function(){add close and open stuff}); tabindex="-1"><i class="icon-th"></i></a>'

Answer 1

Add a event delegation to the container:

$("#container").on("click", ".tool", function(){
    // Close all
    // Open new one
})