[英]Replace text between two words
This question seems to be simple and repetitive here in SO. 在SO中,这个问题似乎很简单,也很重复。
But consider this string: SELECT a, b, c, d FROM
. 但请考虑这个字符串:
SELECT a, b, c, d FROM
。 I want to get only what is between SELECT
and FROM
. 我想只得到
SELECT
和FROM
之间的内容。
Nice so I have found this answer that propose this regex: (?<=SELECT)(.*)(?=FROM)
. 很好,所以我找到了这个答案提出这个正则表达式:
(?<=SELECT)(.*)(?=FROM)
。 It's perfect if lookbehind works in JavaScript, according to this post : 根据这篇文章 ,如果lookbehind在JavaScript中工作,这是完美的 :
Unlike lookaheads, JavaScript doesn't support regex lookbehind syntax
与前瞻不同,JavaScript不支持正则表达式的lookbehind语法
So it won't work(test it in regexpal that is made for JS). 所以它不起作用(在为JS制作的regexpal中测试它)。 This anwser proposes this regex:
SELECT=(.*?)FROM
. 这个anwser提出了这个正则表达式:
SELECT=(.*?)FROM
。 But it includes the two words, so it not fits my needs. 但它包括两个词,所以它不符合我的需要。
The purpose of this is to use in a replace
function to transform this... 这样做的目的是在
replace
函数中使用来改变这个......
SELECT a, b, c, d FROM
into this... 进入这...
SELECT Count(*) FROM
Thank you in advance. 先感谢您。
只需使用捕获组:
"SELECT a, b, c, d FROM".replace(/(SELECT)(.+?)(?= FROM)/, "$1 count(*)")
Try this:- 尝试这个:-
$("button").click(function() {
var srctext = $("#fixme").text();
console.log("old text: " + srctext);
var newtext = srctext.replace(/(SELECT)(.+?)(?= FROM)/, "$1 count(*)");
console.log("new text: " + newtext);
$("#fixme").text(newtext)
});
WORKING JSFIDDLE:- http://jsfiddle.net/tkP74/1597/ 工作JSFIDDLE: - http://jsfiddle.net/tkP74/1597/
好吧,你可以像我在评论中所说的那样把SELECT
放回去:
str.replace(/SELECT (.*?)(?= FROM)/i, "SELECT Count(*)");
正如此特定字符串的正则表达式的替代方法:
str = 'SELECT COUNT(*) ' + str.substr(str.indexOf('FROM'));
Without regex : 没有正则表达式 :
var query = "SELECT a, b, c, d FROM";
var iSelect = query.indexOf("SELECT");
var selLen = "SELECT".length;
var iFrom = query.indexOf("FROM");
if (iSelect >= 0 && iFrom >= 0) {
query = query.replace(query.substring(iSelect + selLen, iFrom), " COUNT(*) ");
console.log(query);
}
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